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taurus [48]
3 years ago
6

4. An ideal solution contains 40 mole percent of A and 60 mole percent of B at 80 oC. The vapor pressure of pure A and B at this

temperature are 480 torr and 890 torr, respectively. Calculate the vapor pressure of the solution.
Chemistry
1 answer:
Vikentia [17]3 years ago
6 0

Answer :  The vapor pressure of the solution is, 726 torr.

Explanation : Given,

Mole percent of A = 40 %

Mole fraction of A = 0.4

Mole percent of B = 60 %

Mole fraction of A = 0.6

Now we have to calculate the partial pressure of A and B.

According to the Raoult's law,

p_i=X_i\times p^o_i

where,

p_i = vapor pressure of gas

p_^o_i = vapor pressure of pure gas  

X_i = mole fraction of gas

p_{A}=X_{A}\times p^o_A

p_{A}=0.4\times 480torr=192torr

and,

p_{A}=X_{A}\times p^o_A

p_{A}=0.6\times 890torr=534torr

Now we have to calculate the vapor pressure of the solution.

P_T=p_{A}+P_{B}

P_T=192torr+534torr

P_T=726torr

Thus, the vapor pressure of the solution is, 726 torr.

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