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ZanzabumX [31]
2 years ago
11

I need help quickly so hurry please

Chemistry
1 answer:
STALIN [3.7K]2 years ago
6 0

Answer:

bruh its a circle :I

Explanation:

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WHY ACETIC ACID IS STRONGER IN STRENGHT THAN CHLOROACETIC ACID ...?
aleksandr82 [10.1K]
For this question, I think it is the other way around. It is true that chloroacetic acid is stronger in strength than acetic acid. Acid strength is measured as the equilibrium constant of the reaction <span>HA -----> H+ + A- 

</span><span> In acetic acid, the anion produced by dissociation is CH3-COO-; in chloroacetic acid it is CH2Cl-COO-. Comparing the two, in the first one the negative charge is taken up mostly by the two oxygen atoms. In the second there is also an electronegative chlorine atom nearby to draw more charge towards itself. Therefore, the charge is less concentrated in the chloroacetate ion than it is in the acetate ion, and, accordingly, chloroacetic acid is stronger than acetic acid. </span>
6 0
3 years ago
When iron rusts in air iron3 oxide is produced. How many moles of oxygen react with 28.0 mol of iron in the rusting reaction 4fe
Marrrta [24]
This the balanced equation based on the question 4Fe + 3O_2  -\ \textgreater \ 2Fe_2O_3.

We then proceed with the following calculations

28.0molFe*(\frac {3molO_2}{4mol Fe})= 21molO_2

The answer is 21molO_2 is produced.
5 0
3 years ago
A proton is fired toward a lead nucleus from very far away. How much initial kinetic energy does the proton need to reach a turn
Olegator [25]

Answer:

The electric force is conservative.

Since

ΔK = −ΔU,

Kf − Ki =Ui −Uf.

We have,

Kf = 0

Ui = 0.

Thus Ki =Uf.

<u>so ,at 10 fm Uf = (2×10)−12 J.</u>

6 0
3 years ago
The barium isotope 133ba has a half-life of 10.5 years. a sample begins with 1.1×1010 133ba atoms. how many are left after (a) 5
Sladkaya [172]
<span>a) 7.9x10^9 b) 1.5x10^9 c) 3.9x10^4 To determine what percentage of an isotope remains after a given length of time, you can use the formula p = 2^(-x) where p = percentage remaining x = number of half lives expired. The number of half lives expired is simply x = t/h where x = number of half lives expired t = time spent h = length of half life. So the overall formula becomes p = 2^(-t/h) And since we're starting with 1.1x10^10 atoms, we can simply multiply that by the percentage. So, the answers rounding to 2 significant figures are: a) 1.1x10^10 * 2^(-5/10.5) = 1.1x10^10 * 0.718873349 = 7.9x10^9 b) 1.1x10^10 * 2^(-30/10.5) = 1.1x10^10 * 0.138011189 = 1.5x10^9 c) 1.1x10^10 * 2^(-190/10.5) = 1.1x10^10 * 3.57101x10^-6 = 3.9x10^4</span>
4 0
3 years ago
Read 2 more answers
A molecule of composition is replicated in a solution containing unlabeled (not radioactive) GTP, CTP, and TTP plus adenine nucl
Lapatulllka [165]

Answer:

Please find the complete question in the attached file.

Explanation:

It would only be radioactive if the DNA molecule that employed the poly-T rand as templates. Its other molecule of the daughter would not have been radioactive as it did not need dATP for its replication. While each strand of the second molecule includes t, simultaneous reproduction dATP from both daughter molecules is needed so that each of those is radioactive.

8 0
3 years ago
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