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3 years ago

Describe three factors that could limit the growth of the prairie dog population

Chemistry

2 answers:

alexira [117]3 years ago

5 0

Answer:

Changes in environment, food source changes and disease?

Explanation:

I dont know what the answer choices are

Mila [183]3 years ago

4 0

Answer:

changes in the environment

Explanation:

like digging big holes.

Hope this helps!

You might be interested in

Sea water contains roughly 158.0g of Nacl per liter. What is the molarity of sodium chloride in sea water?

IrinaK [193]

Molar mass NaCl = 58.5 g/mol

C = 158.0 g/L

Molarity = C / molar mass

M = 158.0 / 58.5

M = 2.7000 M

hope this helps!

6 0

3 years ago

Enter the atomic symbol, including mass number and atomic number, for iodine-130.

WINSTONCH [101]

<u>Answer:</u> The atomic symbol of the given element is $_{53}^{130}\textrm{I}$

<u>Explanation:</u>

The general isotopic representation of an element is given as: $_Z^A\textrm{X}$

where,

Z represents the atomic number of the element

A represents the mass number of the element

X represents the symbol of an element

For the given isotope: 130-iodine

Mass number = 130

Atomic number = 53

Hence, the atomic symbol of the given element is $_{53}^{130}\textrm{I}$

6 0

3 years ago

Formule of the acido perbromico

CaHeK987 [17]

The chemical formula for acido perbromico is HBrO4 or perbromic acid or bromate. It is an inorganic compound and an oxoacid of bromine. When an H+, the –ate ion is –ic acid: one less O is –ous acid, ttwo less is hypo- -ous acid and one more is per- -ic acid.

4 0

3 years ago

A compound made of elements A and B, has a cubic unit cell. There is an A atom at each corner of the cube and an A atom at the c

Lorico [155]

Answer:

A₅B₄

Explanation:

Since we have one atom of element A at the center of each face of the unit cell, since the unit cell is a cubic cell, we have 6 faces. Since the atom on the face of the unit cell is shared with another cell, we have half of it in the unit cell is shared So, the number of atoms per face is 1/2 atom/face × 6 faces = 4 atoms on the faces of the unit cell.

Also, we have 1 atom at each corner of the cubic unit cell. Since there are 8 corner in the cubic unit cell. Also, each atom at the corner is shared with 8 unit cells, so we have 1/8 atom per corner. So, the number of atoms per unit cell is 1/8 atom/corner × 8 corners = 1 atoms at the corners of the unit cell.

So, in total we have 4 + 1 = 5 atoms of element A in the unit cell.

Also, there are 4 atoms of element B in the unit cell.

So, the ratio of atoms of element A to element B is 5 : 4.

A:B = 5:4

So, the empirical formula of the compound containing elements A and B is A₅B₄

5 0

3 years ago

How would you prepare 1.00 L of a 0.400M solution of copper(II)sulfate, CuSO4?

Ber [7]

We need to dilute 0.400 mol of copper (II) sulfate, how do we know, how many weigh of $CuSO_4$ we have to dilute??

It's simple.

$\eta=\frac{m}{MM}$

Using a periodic table we can find the molar mass of $Cu,~~S~~and~~O$

$MM_{CuSO_4}=153.9~g/mol$

Then

$m=\eta*MM$

now we can replace it

$m=0.400*159.6$

$\boxed{\boxed{m=63.84~g}}$

Then we have to dilute 63.84 grams of copper (II) sulfate in 1 L of water to obtain a solution with 0.400M

3 0

3 years ago

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