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otez555 [7]
3 years ago
15

Which is better raw or synthetic materials , and why.

Chemistry
1 answer:
Mars2501 [29]3 years ago
7 0

If there is some reason you cannot get the compound from a natural source, it may be helpful to use a synthetic, yet identical, version. If harvesting the item from nature is too expensive or over-harvesting could damage the environment or destroy habitat, it might be better to synthesize the compound.

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Which element below is the most reactive? Hydrogen chlorine neon oxygen
trapecia [35]

Answer:

Chlorine

Explanation:

Chlorine has an atomic number of 17 and a configuration of 2, 8, 7. In the outermost shell, it has 7 seven electrons which means that it needs just one more electron to attain an octet configuration in that shell. Therefore it's can react quickly with any nearby nucleophile.

5 0
3 years ago
Read 2 more answers
What things can water do while in the gaseous phase?
alisha [4.7K]
Move anywhere and can be anywhere while it is in that phase
8 0
3 years ago
Chemist A burns 10.000 grams of C₂H₆ in a constant-volume container at 25ºC. Chemist B burns an unknown mass of C₂H₆ in a consta
alexandr1967 [171]

Answer:

10.000 grams

Explanation:

For the first law of thermodynamics, the energy must be conserved, that means that the energy in form of heat (Q) must be equal to the sum of work (W) and internal energy(ΔU) :

Q = W + ΔU

ΔU depends on the temperature and W in the variation of pressure and volume. Q depends on the temperature, but also the mass. So, there is the same temperature, ΔU is equal for both reaction, if there is no work done, the heat must be equal for both of them. So the mass such be the same.

5 0
3 years ago
4.80 qt is the same as how many mL?
Marina CMI [18]

Answer:

onverted

Conversion factor: 946.352946

1) mL = Quart * 946.352946

2) mL = 4.8 * 946.352946

3) mL = 4542.4941

3 0
3 years ago
Suppose that 6.2 mL of 2.1 M KOH(aq) is transferred to a 250 mL volumetric flask and diluted to the mark. It was found that 36.9
galina1969 [7]

Answer:

0.928 M

Explanation:

The concentration of acid can be determined by using the volume used and the concentration and volume used of base.

We will use the law of equivalence of moles.

M₁V₁=M₂V₂

M₁ = concentration of base used

V₁ = volume of base used

M₂ = concentration of acid used =? (to be determined)

V₂ = volume of acid used

The initial concentration of KOH used is diluted so let us find the final concentration of KOH after dilution

initial moles = final moles

initial concentration X initial volume = final concentration X final volume

6.2 X 2.1 = 250 X final concentration

final concentration = 0.052 M = M₁

V₁ = 36.9 mL

V₂ = 6.2 mL

Here with each mole of phosphoric acid three moles of KOH are used.

Therefore

3 M₁V₁ = M₂V₂

M₂ = \frac{V_{2}}{3M_{1}V_{1}}=0.928M

3 0
3 years ago
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