KOH+ HNO3--> KNO3+ H2O<span>
From this balanced equation, we know that 1 mol
HNO3= 1 mol KOH (keep in mind this because it will be used later).
We also know that 0.100 M KOH aqueous
solution (soln)= 0.100 mol KOH/ 1 L of KOH soln (this one is based on the
definition of molarity).
First, we should find the mole of KOH:
100.0 mL KOH soln* (1 L KOH soln/
1,000 mL KOH soln)* (0.100 mol KOH/ 1L KOH soln)= 1.00*10^(-2) mol KOH.
Now, let's find the volume of HNO3 soln:
1.00*10^(-2) mol KOH* (1 mol HNO3/ 1 mol KOH)* (1 L HNO3 soln/ 0.500 mol HNO3)* (1,000 mL HNO3 soln/ 1 L HNO3 soln)= 20.0 mL HNO3 soln.
The final answer is </span>(2) 20.0 mL.<span>
Also, this problem can also be done by using
dimensional analysis.
Hope this would help~
</span>
It's a trick question because all of them contain both iconic and covalent bonds.
Hope it helps!! :) have fun
Explanation:
- It is known that the amount of heat necessary to raise the temperature of 1 gram of a substance by
is known as specific heat.
Since, q = 
So, larger is the specific heat of a substance less will be the change in its temperature.
Therefore, olive oil has less specific heat as compared to water. This means that olive oil would get hotter.
- Similarly, the specific heat of gold is lesser than the given materials or metals. Hence, gold will requires less heat to rise its temperature.
As a result, water present in gold will heat readily.
- As the relation between heat and specific heat is as follows.
q = 
Therefore, calculate the amount of heat required by the water as follows.
q = 
= 
= 33440 J
or, = 33.44 kJ (as 1 kJ = 1000 J)
Thus, 33.44 kJ heat would it take to raise the temperature of 100.0 g of water from
to
.