All categories

3 years ago

ASAP! WILL GIVE BRAINIEST

1 answer:

8 0

Create and use more electricity then previously used before. A lot of power is created by burning fossil fuels, the burning of them will be increased so more is needed to give power to everyone.

You might be interested in

How many electrons are in the highest occupied energy level of these atoms?

natima [27]

A. Barium with 56 is correct

7 0

3 years ago

Which of the following is an example of the characteristic of movement?

vagabundo [1.1K]

A. The kitten shivers like she’s cold

those link share ppl are SOOOOOO ANNOYING

5 0

3 years ago

Which two changes of state can be caused by removing thermal energy from a substance? choose two

crimeas [40]

Answer:

B and C

Explanation:

The correct answer is Condensation and Deposition

4 0

3 years ago

Read 2 more answers

What did Zoya and her freind do in response

Mama L [17]

In response of what like what’s the full clear question

5 0

3 years ago

The half-life of a first-order reaction is 13 min. If the initial concentration of reactant is 0.13 M, it takes ________ min for

Zigmanuir [339]

Answer:

Therefore it takes 8.0 mins for it to decrease to 0.085 M

Explanation:

First order reaction: The rate of reaction is proportional to the concentration of reactant of power one is called first order reaction.

A→ product

Let the concentration of A = [A]

$\textrm{rate of reaction}=-\frac{d[A]}{dt} =k[A]$

$k=\frac{2.303}{t} log\frac{[A_0]}{[A]}$

[A₀] = initial concentration

[A]= final concentration

t= time

k= rate constant

Half life: Half life is time to reduce the concentration of reactant of its half.

$t_{\frac{1}{2} }=\frac{0.693}{k}$

Here $t_{\frac{1}{2} }=0.13 min$

$k=\frac{0.693}{t_{\frac{1}{2}} }$

$\Rightarrow k=\frac{0.693}{13 }$

To find the time takes for it to decrease to 0.085 we use the below equation

$k=\frac{2.303}{t} log\frac{[A_0]}{[A]}$

$\Rightarrow t=\frac{2.303}{k} log\frac{[A_0]}{[A]}$

Here , $k=\frac{0.693}{13 }$ , [A₀] = 0.13 m and [ A] = 0.085 M

$t=\frac{2.303}{\frac{0.693}{13} } log(\frac{0.13}{0.085})$

$\Rightarrow t= 7.97\approx 8.0$

Therefore it takes 8.0 mins for it to decrease to 0.085 M

7 0

3 years ago