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Luden [163]
2 years ago
9

8. Write a balanced chemical equation showing how you could prepare each of the following salts from an

Chemistry
1 answer:
polet [3.4K]2 years ago
6 0

Answer:

according to my reading

use own words

Explanation:

Salts are combinations of acids and bases. The cation comes from a base and the anion from an acid. Therefore, to make KNO3 we react KOH and HNO3. See how that is done? We write K and add OH to make KOH. We take NO3 and add H to make HNO3.

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miss Akunina [59]

Answer: The value of K_{c} for this reaction is 250000.

Explanation:

The given equation is as follows.

2NH_{3}(g) + 3I_{2}(g) \rightleftharpoons N_{2}(g) + 6HI(g)

N_{2}(g) + 3H_{2}(g) \rightleftharpoons 2NH_{3}(g); K_{c_{1}} = 0.50   ... (1)

H_{2}(g) + I_{2}(g) \rightleftharpoons 2HI(g); K_{c_{2}} = 50  ... (2)

To balance the atoms, multiply equation (2) by 3. Hence, the equation (2) can be re-written as follows.

3H_{2}(g) + 3I_{2}(g) \rightleftharpoons 6HI(g); K_{c_{2}} = (50)^{3}  ... (3)

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3I_{2} - N_{2} \rightleftharpoons 6HI - 2NH_{3}

This equation can also be re-written as follows.

3I_{2} + 2NH_{3} \rightleftharpoons N_{2} + 6HI

This equation is similar to the equilibrium equation given to us.

Therefore, during this subtraction the equation constants get divided as follows.

K^{'}_{c} = \frac{K_{c_{2}}}{K_{c_{1}}}\\= \frac{(50)^{3}}{0.50}\\= 250000

Thus, we can conclude that the value of K_{c} for this reaction is 250000.

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