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nadya68 [22]
3 years ago
6

32 to 36 Directions: Find the area for the

Mathematics
1 answer:
dolphi86 [110]3 years ago
5 0

Answer:

C

Step-by-step explanation:

Area of a circle is calculated by squaring the radius then multiplying by pi. Eight squared is sixty-four, then multiplied by pi you get 201.

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Answer:

-29x-5

Step-by-step explanation:

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What is the area of triangle IHC?
madam [21]

Answer:

28 cm^2

Step-by-step explanation:

<em><u>The formula for finding the area of a triangle is:</u></em>

<em><u /></em>\frac{1}{2} bh

<em><u>The "b," is the base (7), and the "h," is the height (8):</u></em>

\frac{1}{2} (7)(8)

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3 years ago
Will mark correct answer brainly.
Furkat [3]

Answer:

Step-by-step explanation:

Volume of Cone =1 \div 3 \times \pi \times r { \times h}^{2}1÷3×π×r×h

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4 0
2 years ago
For the parallelogram ABCD the extensions of the angle bisectors AG and BH intersect at point P. Find the area of the parallelog
natita [175]

Answer:

The area of a parallelogram is 360 in.²

Step-by-step explanation:

Where DG = GH

GP = 12 in.

AB = 39 in.

∠DAB + ∠ABC = 180° (Adjacent angles of a parallelogram)

Whereby ∠DAB is bisected by AG and ∠ABC is bisected by BH

Therefore, ∠GAB + ∠HBA = 90°

Hence, ∠BPA = 90° (Sum of interior angles of a triangle)

cos(\angle GAB) = \dfrac{AP}{AB} = \dfrac{AP}{39} = \dfrac{GP}{GH} =\dfrac{12}{GH}

We note that ∠AGD = ∠GAB (Alternate angles of parallel lines)

∴ ∠AGD = ∠AGD since ∠AGD = ∠GAB (Bisected angle)

Hence AD = DG (Side length of isosceles triangle)

The bisector of ∠ADG is parallel to BH and will bisect AG at point Q

Hence ΔDAQ  ≅ ΔDGQ ≅ ΔGPH and AQ = QG = GP

Hence, AP = 3 × GP = 3 × 12 = 36

cos(\angle GAB) = \dfrac{AP}{AB} = \dfrac{36}{39}

\angle GAB = cos^{-1} \left (\dfrac{36}{39}  \right )

∠GAB = 22.62°

cos(\angle GAB) =  \dfrac{36}{39} = \dfrac{12}{GH}

GH =  \dfrac{39}{36} \times {12}

GH = 13 in.

∴ AD 13 in.

BP = 39 × sin(22.62°) = 15 in.

GH = √(GP² + HP²)

∠DAB = 2 × 22.62° = 45.24°

The height of the parallelogram = AD × sin(∠DAB) =  13 × sin(45.24°)

The height of the parallelogram = 120/13 =  9.23 in.

The area of a parallelogram = Base × Height = (120/13) × 39 = 360 in.²

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3 years ago
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2x + 2y - x - (8 + 1)?
kotegsom [21]

Answer:

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