Answer:
6.38 x 10^4 J
Explanation:
d = 0.33 cm = 0.33 x 10^-2 m, Area = 87 x 36 cm^2 = 0.87 x 0.36 m^2
ΔT = 14 degree C, t = 1 min = 60 second
K = 0.8 W / m K
Heat = K A ΔT t / d
H = 0.8 x 0.87 x 0.36 x 14 x 60 / (0.33 x 10^-2)
H = 6.38 x 10^4 J
multiply the six sides of the cube(LB), since length is 2000, then breadth will be 2000 also
Answer:
*The same balloon put into the freezer would be smaller and shriveled.
* The volume decreases as the temperature decreases.
* using a hypothetical starting volume of 2 liters in the balloon at 42 degrees Celsius, we can use the equation V1/T1 =V2/T2
V2= 1.54 liters which proves when temperature decreases , volume decreases as well.
Explanation:
The volume increases as the temperature increases, and volume decreases as the temperature decreases.
using a hypothetical starting volume of 2 liters in the balloon at 42 degrees Celsius, we can use the equation V1/T1 =V2/T2
Change Celsius to kelvin by adding 273.
2 liters/ 315 K = V2/243 K
Cross multiply and then divide by 315 to find V2
2 liters x 243 K / 315 K = V2
The Kelvin cancels itself out.
486 liters /315=V2
V2= 1.54 liters.
This proves that when the temperature decreases , so does the volume.
Answer:
v₁ = u₁/2√3 ≈ 0.866u₁
v₂ = u₁/2 = 0.5u₁
θ = 60°
Explanation:
let u₁ be the initial velocity of the first ball
let v₁ be the final velocity of the first ball
let v₂ be the final velocity of the second ball
For elastic collisions, the angle between the departing masses is 90°
assume the first ball initially moves along the x axis in the positive direction
conservation of momentum
In the y direction, initial momentum is zero
After the collision
mv₁sin30 = mv₂sin60
½v₁ = ½√(3)v₂
v₁ = √(3)v₂
in the x direction,
mu₁ = mv₁cos30 + mv₂cos-60
u₁ = v₁cos30 + v₂cos60
u₁ = (√(3)v₂)½√(3) + ½v₂
u₁ = 2v₂
v₂ = u₁/2
v₁ = √(3)v₂ = √(3)(u₁/2)
