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Nataliya [291]
3 years ago
12

What involves extensive in depth studies of an individual?

Physics
1 answer:
GuDViN [60]3 years ago
5 0
 should be lifespan dovelopment
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A bus leaves New York City, takes a non-direct route and arrives in St. Louis, Missouri 23 hours, 16 minutes later. If the dista
german

Answer:

vavg = 53.7 km/h

Explanation:

In order to find the magnitude of the bus'average velocity, we need just to apply the definition of average velocity, as follows:

vavg =\frac{xf-xo}{t-to}

where xf - xo = total displacement = 1250 Km

If we choose t₀ = 0, ⇒ t = 23h 16'= 23h + 0.27 h = 23.27 h

⇒ vavg =\frac{1250 km}{23.27h}  =  53.7 Km/h

8 0
3 years ago
MULTIPLE CHOICE PLEASE HELP QUICK!!!!!!
vekshin1
 i would choose a for 945 and a for faster
5 0
3 years ago
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A hockey puck is hit on a frozen lake and starts moving with a speed of 13.60 m/s. Exactly 6.2 s later, its speed is 7.20 m/s. (
stellarik [79]

Answer:

-1.03 m/s²

Explanation:

Acceleration: This can be defined as the rate of change of velocity. The S. I unit of acceleration is m/s².

Mathematically, acceleration is expressed as

a = (v-u)/t ........................ Equation 1

Where a = acceleration, v = final velocity, u = initial velocity, t  = time.

Given: u = 13.60 m/s, v = 7.20 m/s t = 6.2 s.

Substituting into equation 2

a = (7.20-13.60)/6.2

a = -6.4/6.2

a = -1.03 m/s²

Note: a is negative because, the hockey puck is decelerating.

Hence the average acceleration = -1.03 m/s²

3 0
3 years ago
I'll give brainliest if you give me a good awnser. :)
lbvjy [14]

Answer:

0.5

Explanation:

4 0
3 years ago
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"Place ½ teaspoon of baking soda in each large container. If the baking soda is lumpy, first place it on a small plate and use t
photoshop1234 [79]

Answer:

The reaction only takes place if the reactants are in contact, then the surface exposed is very important because as the exposed surface of the reactants increases, the reaction velocity also increases. If the lumps are not broken up, a big amount of baking soda would be only available to react after the surrounding soda has already reacted.

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4 years ago
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