Normally, the expected bond angle of the compound that is SF2 should actually be around 98° and it had the same bent geometry just like water. The hybridization of the central atom which is sulphur is Sp3. If the sulphur and Fluorine p- orbitals overlap and the two Fluorine atoms causes repulsion we should have around 98° bond angle for SF2.
The bond angle of water is around 104.5° and the interesting part is that oxygen which is the central atom of H2O is smaller than sulphur in SF2. So, we can just say the ideal bond angle for SF2 should be around 109.5°.
So, if we are to choose from this option the most correct option is that of option B which is 109.5°. But, assuming we have 98° in the options you should go for the 98°.
