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il63 [147K]
3 years ago
13

How many atoms are in 3.690 moles of oxygen

Chemistry
1 answer:
sweet [91]3 years ago
4 0

1 mole of any substance contains Avogadro's number.  

So, 1 mole of O2= 6.023x10^23 molecules  

3 mole of O2= 6.023x10^23x3 molecules  

= 1.8069x10^24 molecules  

Each molecule of Oxygen has 2 atoms.  

therefore,  

1.8069x10^24 molecules= 1.8069x10^24 x 2 atoms  

= 3.6138x10^24 atoms.

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In another experiment, if 80 xo3 molecules react with 104 brz3 molecules how many br2 molecules will be produced which reactant
BaLLatris [955]

This is an incomplete question, here is a complete question.

The balanced chemical reaction is:

6XO_3+8BrZ_3\rightarrow 6XZ_4+4Br_2+9O_2

In another experiment, if 80 XO_3 molecules react with 104 BrZ_3 molecules. How many Br_2 molecules will be produced which reactant will be used up in the reaction.

Answer : The number of molecules of Br_2  will be, 52 molecules and BrZ_3 reactant will be used up in the reaction because it is a limiting reagent and it limits the formation of product.

Explanation :

The balanced chemical reaction is:

6XO_3+8BrZ_3\rightarrow 6XZ_4+4Br_2+9O_2

First we have to determine the limiting reagent.

From the balanced reaction we conclude that,

As, 8 molecules of BrZ_3 react with 6 molecule of XO_3

So, 104 molecules of BrZ_3 react with \frac{104}{8}\times 6=78 molecule of XO_3

From this we conclude that, XO_3 is an excess reagent because the given moles are greater than the required moles and BrZ_3 is a limiting reagent and it limits the formation of product.

Now we have to calculate the molecules of Br_2

From the reaction, we conclude that

As, 8 molecules of BrZ_3 react to give 4 molecules of Br_2

So, 104 molecules of BrZ_3 react to give \frac{104}{8}\times 4=52 molecules of Br_2

Hence, the number of molecules of Br_2  will be, 52 molecules and BrZ_3 reactant will be used up in the reaction because it is a limiting reagent and it limits the formation of product.

4 0
3 years ago
How much energy does it take to melt 2 kg of ice? (Refer to table of<br> constants for water.)
ioda
It would be C

2 kg x 1000 g/kg x 1mol/18.02 x 6.03 kj/mol = 669kj


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Answer:

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erik [133]
A: C₆H₁₂O₆ + 6H₂O + 6O₂

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8 0
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Why do we use moles when calculating empirical chemical formulas, but not the mass?
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Answer:

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Explanation:

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