How many atoms are in 3.690 moles of oxygen

1 answer:

sweet [91]3 years ago

4 0

1 mole of any substance contains Avogadro's number.

So, 1 mole of O2= 6.023x10^23 molecules

3 mole of O2= 6.023x10^23x3 molecules

= 1.8069x10^24 molecules

Each molecule of Oxygen has 2 atoms.

therefore,

1.8069x10^24 molecules= 1.8069x10^24 x 2 atoms

= 3.6138x10^24 atoms.

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Vikentia [17]

Answer:

636 balloons

Explanation:

If we assume that helium gas follows an ideal gas behaviour, we can use the ideal gas law to solve this problem as follows:

We consider two different states, the initial given by the conditions of the problem statement and the final, when the tank reaches atmospheric pressure and it's no longer able to fill balloons: $P_{1}=160 atm\\V_{1}=12 L\\P_{2}=1 atm\\V_{2}= ?$
To find out what would be this volume 2, we use the Boyle's Law: $P_{1}V_{1}=P_{2}V_{2}\\V_{2}=\frac{P_{1}V_{1}}{P_{2}} \\V_{2}=\frac{160 atm \times 12L}{1 atm}\\V_{2}=1920 L$
Now we find the available volume to fill the balloons by substracting both, volume 2 and volume 1: $V_{b}=V_{2}-V_{1}=1920L-12L=1908 L$
Finally, we determine the quantity of ballons by dividing that available volume between the volume of each ballon: $B=\frac{1908L}{3L} =636 balloons$