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3 years ago

Identify the products in the reaction HCl+NaOH=NaCl+H2O

Chemistry

1 answer:

valentina_108 [34]3 years ago

5 0

NaCl and H2O.

The products are typically the elements/compounds on the right side of the equation or the right side of the arrow. The left side of the arrow would be the reactants of the equation.

Hope this helps!

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Assuming all other variables are constant, if the pressure of a gas is increased from 2. atm to 6 atm the volume would change fr

Leona [35]

Answer:

2.0 Liters

Explanation:

Boyles law

P1 V1 = P2 V2

V2= P1 V1 / V2

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3 years ago

What is the molarity of solution that is 5.50 percentage by mass oxalic acid and has a density of 1.024 g/ml

Y_Kistochka [10]

Answer:

0.6257 M is the molarity of solution that is 5.50 percentage by mass oxalic acid.

Explanation:

Mass percentage of oxalic acid = 5.50%

This means that in 100 grams of solution there are 5.50 grams of oxalic acid.

Mass of solution , m = 100

Volume of the solution = V

Density of the solution = d = 1.024 g/mL

$V=\frac{m}{d}=\frac{100 g}{1.024 g/mL}=97.66mL$

V = 97.66 mL = 0.09766 L

(1 mL = 0.001 L)

Moles of oxalic acid = $\frac{5.50 g}{90 g/mol}=0.06111 mol$

$Molarity=\frac{\text{Moles of solute}}{\text{Volume of solution in L}}$

The molarity of the solution :

$=\frac{0.06111 mol}{0.09766 L}=0.6257M$

0.6257 M is the molarity of solution that is 5.50 percentage by mass oxalic acid.

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3 years ago

CONCLUSIONS: Suppose a student titrated a sample of monoprotic acid of unknown concentration using a previously standardized sol

Zolol [24]

Concentration of unknown acid is 0.061 M

Given:

Concentration of NaOH = 0.125 M

Volume of NaOH = 24.68 mL

Volume of acid solution = 50.00 mL

To Find:

Concentration of the unknown acid

Solution: Concentration is the abundance of a constituent divided by the total volume of a mixture. The concentration of the solution tells you how much solute has been dissolved in the solvent

Here we will use the formula for concentration:

M1V1 = M2V2

0.125 x 24.68 = 50 x M2

M2 = 0.125 x 24.68 / 50

M2 = 0.061 M

Hence, the concentration of unknown acid is 0.061 M

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Cilium part of a cell

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