Answer:
Q = 114349.5 J
Explanation:
Hello there!
In this case, since this a problem in which we need to calculate the total heat of the described process, it turns out convenient to calculate it in three steps; the first one, associated to the heating of the liquid water from 40 °C to 100 °C, next the vaporization of liquid water to steam at constant 100 °C and finally the heating of steam from 100 °C to 115 °C. In such a way, we calculate each heat as shown below:
Thus, the total energy turns out to be:
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Benzene, C6H6 is miscible with hexane (C6H14) but iron (IIl) nitrate, and Sulfuric acid, H2SO4Fe(NO3)3 are not miscible with hexane (C6H14)
Since organic or non polar dissolves in nom polar solvent.here both benzene and hexane (C6H14) are non polar solvents.But iron (IIl) nitrate, Fe(NO3)3 and Sulfuric acid, H2SO4 are inorganic and polar, therefore cannot dissolve with non polar solvent like hexane.
Miscible is a flowery heard that oil and water aren't very miscible substances, while seltzer and orange juice are miscible and scrumptious.Miscible beverages are also described as liquids that can blend to form a homogeneous solution. Miscible drinks generally blend with out limit, meaning they may be soluble at all quantities.
Miscible approach the materials blend completely. If substances are miscible, they're also absolutely soluble in each other no matter the order of creation. for example, tetrahydrofuran and water are miscible.
Learn more about miscible liquids here:-brainly.com/question/10423831
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Organic chemistry is all about CARBON!!!!!!
Answer:
Explanation:
By definition, <em>half neutralization</em> is the point at which half of the acid has been neutralized.
The neutralization reaction that you are studying is the acid-base reaction:
- HCl (aq) + NaOH (aq) → NaCl(aq) + H₂O (aq)
Then, since the starting molarity of the acid (HCl) is 0.2 M, you just need to find half of that concentration:
- Half molarity = M / 2 = 0.2 M / 2 = 0.1 M
So, the answer is the first choice: a. 0.1 M.
The balanced chemical reaction:
C3H8 + 5O2 = 3CO2 + 4H2O
We are given the amount of the carbon dioxide to be produced. This will be the starting point of our calculations.
<span>43.62 L CO2 ( 1 mol CO2 / 22.4 L CO2 ) (5 mol O2 / 3 mol CO2 ) (
22.4 L O2 / 1 mol O2) = 72.7 L O2</span>
