Answer:
a. MgO(s) + H2CO3(aq) → MgCO3(s) + H2O(l) DOUBLE DISPLACEMENT REACTION.
b. 2KNO3(s)→2KNO2 (s) + O2(8) DESCOMPOSITION REACTION.
c. H2(g) + CuO(s) → Cu(s) + H2O(1) SINGLE DISPLACEMENT REACTION.
d. NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(1) COMBUSTION REACTION.
e. H2(8) + Cl2(g) → 2HCl(8) SYNTHESIS REACTION.
f. SO3(g) + H2O(1)→ H2SO4(aq) SYNTHESIS REACTION.
Atomic mass of F: 19.0 g/mol
Atomic mass of S: 32.1 g/mol
1.18 g F = [1.18 g / 19.0 g / mol] = 0.062 mol F
1 g S = 1 g/ 32.1 g/mol = 0.031 mol S
Divide by 0.031
0.062 mol F / 0.031 = 2 mol F
0.031 mol S / 0.031 = 1 mol S
SF2 Then X = 2
Verification:
F2 = 2*19.0 g = 38 g F
S = 32.1 g
36 gF / 32.1 g S = 1.18 g F / g S
Answer:
8.34
Explanation:
1) how much moles of NH₃ are in the reaction;
2) how much moles of H₂ are in the reaction;
3) the required mass of the H₂.
all the details are in the attachment; the answer is marked with red colour.
Note1: M(NH₃) - molar mass of the NH₃, constant; M(H₂) - the molar mass of the H₂, constant; ν(NH₃) - quantity of NH₃; ν(H₂) - quantity of H₂.
Note2: the suggested solution is not the shortest one.
Answer:
So, Luke and Sian has to increase the pH of the soil by adding base to it.
Explanation:
The pH is defined as the negative logarithm of the hydrogen ion concentration in their aqueous solution.
![pH=-\log[H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%5BH%5E%2B%5D)
- With increase in hydrogen ion concentration the pH value decreases.
- With decrease in hydrogen ion concentration the pH value increases.
The pH of the soil after testing it on a kit comes out be 5.0, but they both need pH of the soil to 6.5.
Comparison of pH of soil:
= 5.0 < 6.5
= High hydrogen ion concentration > High hydrogen ion concentration
So, Luke and Sian has to increase the pH of the soil by adding base .Doing so will decrease the hydrogen ion concentration in the soil (where as addition of acid lower the pH of soil).