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nata0808 [166]
3 years ago
8

You are explaining to your friends why astronauts feel weightless while orbiting in the space shuttle. They ask you to prove thi

s mathematically. Calculate the acceleration of gravity 250 km above the Earth’s surface in terms of g.
(Use Rearth = 6.38x103 km.)
Physics
1 answer:
meriva3 years ago
5 0

Answer:

Explanation:

Force of gravity = GMm/r^2 = ma

a being the acceleration due to gravity at some distance r from the center of the Earth.  I'll use 6400 km for the radius of the Earth so r = 6734 km or 6734000 meters

a = GM/r^2

plugging in G = 6.67 x 10^-11

M is the mass of the Earth = 6 x 10^24

and r is from above

a = 8.825 m/s^2  = 0.9g

so 90% the acceleration of gravity on the surface.

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34 + 3.7395 = 37.7395
The answer is 38.
The answer is written to two significant figures because the smallest given  number of significant figure is 2.
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4 years ago
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In a double slit experiment, if the separation between the two slits is 0.050 mm and the distance from the slits to a screen is
meriva

The spacing between the first-order and second-order bright fringes is 3 cm. Hence, this is the required solution.

<h3>What is double slit experiment?</h3>

The double-slit experiment serves as a proof in current physics that both light and matter may exhibit properties of classically defined waves and particles. It also illustrates the inherently probabilistic nature of quantum mechanical events. Thomas Young carried out the first experiment of this kind employing light in 1802, illustrating how light behaves like a wave. It was formerly believed that light was made up of either waves or particles. About a century later, with the advent of modern physics, it was discovered that light may in fact exhibit behaviour like that of both waves and particles. The identical behaviour of electrons was first shown by Davisson and Germer in 1927, and it was later extended to atoms and molecules.

The separation between the slits, d = 0.05mm = 5×10⁻⁵ m

The distance from the slits to a screen, D = 2.5 m

Let x is the spacing between the first-order and second-order bright fringes when coherent light of wavelength 600 nm illuminates the slits,

λ = 600nm = 6× 10⁻⁷ m  

We know that the bright fringe is given by :

y = nλD/d

So, the spacing between the first-order and second-order bright fringes is :

x = 2λD/d - λD/d

x =  λD/d

x = 6 × 10⁻⁷ × 2.5/5 × 10⁻⁵

x = 0.03 m

or

x = 3 cm

So, the spacing between the first-order and second-order bright fringes is 3 cm. Hence, this is the required solution.

to learn more about double slit experiment go to -

brainly.com/question/28108126

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8 0
1 year ago
What is the work done by a car's braking system when it slows the 1500-kg car from an initial speed of 96 km/h down to 56 km/h i
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Answer:

-352.275KJ

Explanation:

We are given that

Mass of car=1500kg

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1km/h=\frac{5}{18}m/s

Final speed of car=v=56km/h=56\times \frac{5}{18}=15.56m/s

Distance traveled by car=s=55m

We have to find the work done by the car's braking system.

Using third equation of motion

v^2-u^2=2as

(15.56)^2-(26.67)^2=2a(55)

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Work done by a car's barking system=-\frac{352275}{1000}=-352.275KJ

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7 0
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Why is creativity important in constructing scientific questions?
jeka94
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Answer:

232

U

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Explanation:

mass number=protons add neutrons

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8 0
3 years ago
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