Imagine that an electron in an excited state in a nitrogen molecule decays to its ground state, emitting a photon with a frequen
cy of 8.88×1014 Hz . What is the change in energy, ΔE, that the electron undergoes to decay to its ground state?
1 answer:
Answer: 5.884×10^-19 J
Explanation:
The change in energy will be the product of the planck constant and the frequency of radiation.
ΔE = hf
Where h = planck constant = 6.626×10^-34 m²kg/s
f = 8.88×10^14 Hz
ΔE = 6.626×10^-34 × 8.88×10^14 = 58.84×10^-20 = 5.884×10^-19 J
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