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Bumek [7]
3 years ago
7

Imagine that an electron in an excited state in a nitrogen molecule decays to its ground state, emitting a photon with a frequen

cy of 8.88×1014 Hz . What is the change in energy, ΔE, that the electron undergoes to decay to its ground state?
Physics
1 answer:
wariber [46]3 years ago
5 0

Answer: 5.884×10^-19 J

Explanation:

The change in energy will be the product of the planck constant and the frequency of radiation.

ΔE = hf

Where h = planck constant = 6.626×10^-34 m²kg/s

f = 8.88×10^14 Hz

ΔE = 6.626×10^-34 × 8.88×10^14 = 58.84×10^-20 = 5.884×10^-19 J

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3 years ago
The mass of a proton is approximately equal to
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Answer:

1.6726\cdot 10^{-27} kg

Explanation:

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3 0
3 years ago
An object has a coefficient of static friction of 0.3 and a normal force of 30 N. Find the force of static friction.
gladu [14]

Answer:

9N

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7 0
3 years ago
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a crate is being lifted into a truck. if it is moved with a 2470n force and 3650 j of work is done , then how far is the crate b
SVEN [57.7K]

Answer:

The crate was being lifted by a height of 1.48 meters.

Explanation:

In an attempt o move a crate;

Force applied = 2470 N

Work done by the force = 3650 J

We know that the work done is defined as the force used to move an object to a distance.

Given the Force used and the work done by that Force, we need to find out the distance the crate was lifted to.

Work done is defined as:

Work = Force*distance covered in the direction of the force

3650 = 2470*distance

distance = 3650/2470

distance = 1.48 meters

4 0
3 years ago
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