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Zolol [24]
3 years ago
9

Solve the system: 2.5(x−3y)−3=−3x+0.5 3(x+6y)+4=9y+19

Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
3 0

Answer:

The value of x and y that satisfy the equations is x = 2 and y = 1

Step-by-step explanation:

Given

2.5(x−3y)−3=−3x+0.5

3(x+6y)+4=9y+19

Required.

Find x and y

We start by opening all brackets

2.5(x−3y)−3=−3x+0.5 becomes

2.5x - 7.5y - 3 = -3x + 0.5

Collect like terms

2.5x + 3x - 7.5y = 3 + 0.5

5.5x - 7.5y = 3.5 ---- Equation 1

In similar vein, 3(x+6y)+4=9y+19 becomes

3x + 18y + 4 = 9y + 19

Collect like terms

3x + 18y - 9y = 19 - 4

3x + 9y = 15

Multiply through by ⅓

⅓ * 3x + ⅓ * 9y = ⅓ * 15

x + 3y = 5

Make x the subject of formula

x = 5 - 3y

Substitute 5 - 3y for x in equation 1

5.5(5 - 3y) - 7.5y = 3.5

27.5 - 16.5y - 7.5y = 3.5

27.5 - 24y = 3.5

Collect like terms

-24y = 3.5 - 27.5

-24y = -24

Divide through by - 24

y = 1

Recall that x = 5 - 3y.

Substitute 1 for y in this equation

x = 5 - 3(1)

x = 5 - 3

x = 2

Hence, x = 2 and y = 1

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Based on this the correct system of hypothesis are:

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Alternative hypothesis: \mu >78

And the best option for this case is:

a. H0:\mu=78 vs. H1:\mu>78 .

Step-by-step explanation:

For this case we have the following previous info given:

\mu = 78 represent the true mean

\sigma =10 represent the true deviation

The teacher select a sample of n =15 students.  And he wanted to know if teaching a smaller class was more effective and students performed better, that means if \mu >78 and he obtaind a sample mean of \bar X>83.

Based on this the correct system of hypothesis are:

Null hypothesis: \mu =78

Alternative hypothesis: \mu >78

And the best option for this case is:

a. H0:\mu=78 vs. H1:\mu>78 .

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If f(x) = 5x – 1, then f^-1(x)=
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Answer:

\boxed{\sf \ \ \ f^{-1}(x)=\dfrac{x+1}{5} \ \ \ }

Step-by-step explanation:

hello

f(x)=5x-1

what can we say about f^{-1}(x) ?

(fof^{-1})(x)=x=f(f^{-1}(x))=5f^{-1}(x)-1

so

5f^{-1}(x)-1=x\\ 5f^{-1}(x)-1+1=5f^{-1}(x)=x+1 \ \ \ add \ \ 1\\   f^{-1}(x)=\dfrac{x+1}{5} \ \ \ divide \ \ by  \ \ 5

hope this helps

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3 years ago
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