Answer:
ΔSº= -41,2 J/molK
Explanation:
For a general equation aA +bB → cC + dD
ΔSº= c*SºC + d*SºD - a*SºA - b*SºB
ΔSº= SºAL2O3 + 2SºFe - SºFe2O3 - 2SºAl = (51 + 54.4 - 90 - 56.6)J/molK = -41,2 J/molK
Answer:
Molecules in liquids are held to other molecules by intermolecular interactions, which are weaker than the intramolecular interactions that hold the atoms together within molecules and polyatomic ions.
It has a decrease in oxidation number
The process of reduction is when the oxidation number of a chemical specie is lowered, or when the specie gains electrons. A chemical specie undergoing reduction will act as an oxidizing agent, because it will oxidize the other reactant by itself getting reduced.
Answer:
0.48atm
Explanation:
Firstly, we need to know the mole ratio of the oxygen gas involved. To do this, we simply place the number of moles of the oxygen over the sum of both gases.
This would be 3/(3+7) = 0.3
Now, to get the partial pressure contributed by the oxygen gas, we simply multiply the 0.3 by the total pressure
Hence, the partial pressure of oxygen = the mole fraction of oxygen * the total pressure.
= 0.3 * 1.6 = 0.48atm