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3 years ago

Calculate the pH of a solution whose H3O+ concentration is 2.1 x 10-3 M. Is the solution acidc, basic, or neutral?

Chemistry

1 answer:

Leona [35]3 years ago

5 0

Answer:

Option A, The pH of the solution is 2.7 and the solution is acidic

Explanation:

As we know,

pH = - log [H3O+]

Substituting the given values, we get

pH = - log [2.1 x 10-3 M]

pH = - (-2.678)

pH = 2.678 or 2.7

The solution is acidic as pH value is less than 7

Hence, option A is correct

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You know that 8.9 moles of solute particles are dissolved in that liquid solution. If the molarity of the solution is 25 M, how

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Answer:

V = 0.356 L

Explanation:

In this case, we need to use the following expression:

M = n/V (1)

Where:

M: molarity of solution (mol/L or M)

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3 years ago

The true absorbance for a 1.0 x 10 −5 M solution is 0.7526. If the percentage stray light for a spectrophotometer is 0.56%, calc

Korvikt [17]

Answer:

The percentage deviation is $\Delta M = 1.87$ %

Explanation:

From the question we are told that

The concentration is of the solution is $C = 1.0*10^{-5} M$

The true absorbance A = 0.7526

The percentage of transmittance due to stray light $z = 0.56$ % $=\frac{0.56}{100} = 0.0056$

Generally Absorbance is mathematically represented as

$A = -log T$

Where T is the percentage of true transmittance

Substituting value

$0.7526 = - log T$

$T = 10^{-0.7526}$

$= 0.177$

$= 17.7$ %

The Apparent absorbance is mathematically represented

$A_p = -log (T +z)$

Substituting values

$A_p = -log(0.177 + 0.0056)$

$= -log(0.1826)$

= 0.7385

The percentage by which apparent absorbance deviates from known absorbance is mathematically evaluated as

$\Delta A = \frac{A -A_p}{A} * \frac{100}{1}$

$= \frac{0.7526 - 0.7385}{0.7526} * \frac{100}{1}$

$\Delta A = 1.87$ %

Since Absorbance varies directly with concentration the percentage deviation of the apparent concentration from know concentration is

$\Delta M = 1.87$ %

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