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BigorU [14]
3 years ago
8

How many grams of sucrose (C12H22O11) would be in 8.7 L of a 6.81M solution of sucrose

Chemistry
1 answer:
VladimirAG [237]3 years ago
7 0
<h3><u>Answer;</u></h3>

= 20,280.25 g or 20.28 Kg

<h3><u>Explanation;</u></h3>

Number of moles, n = Molarity × Volume

Molarity = 6.81 M

Volume = 8.7 L

Number of moles = 6.81 × 8.7

                             = 59.247 moles

Mass = Moles × Molar mass

         = 59.247 ×  34.2 g/mol

          = 20,280.25 or

          = 20.28 Kg

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<h3>Further explanation</h3>

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