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kumpel [21]
3 years ago
11

For the following reaction, 4.51 grams of water are mixed with excess silicon tetrafluoride. The reaction yields 8.73 grams of h

ydrofluoric acid. SiF4 (s) + 2H2O (l) 4HF (aq) + SiO2 (s) (1) What is the theoretical yield of hydrofluoric acid?
Chemistry
1 answer:
xxMikexx [17]3 years ago
3 0

Answer:

Theoretical yield is 10.0g of HF.

Explanation:

Theoretical yield is defined as the yield of a reaction assuming a 100%.

In the reaction:

SiF₄(s) + 2H₂O(l) → 4HF(aq) + SiO₂(s)

2 moles of water produce 4 moles of HF.

4.51g of H₂O are:

4.51g ₓ (1mol/18.02g) = 0.250moles of water. Moles of HF:

0.250moles H₂O ₓ (4mol HF/2mol H₂O) = 0.500mol HF

In grams:

0.500mol HF ₓ (20.01g / 1mol) = <em>10.0g of HF - theoretical yield-</em>

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I hope it helps!

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Answer:

\boxed{\text{exhaust stroke}}

Explanation:

The four strokes are

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7 0
3 years ago
Convert 0.00200 g into Mg and answer in scientific notation:
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Since you go straight across its just multiplication so 0.00200x1000=200mg

To answer it in scientific notation it should just be 2.00x10^{2} mg

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Which of the following are in the human brain?
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A reaction of importance in the formation of smog is that between ozone and nitrogen monoxide described by O 3 ( g ) + NO ( g )
Aleksandr [31]

Answer:

(a) 7.11x10⁻⁴ M/s

(b) 2.56 mol.L⁻¹.h⁻¹

Explanation:

(a) The reaction is:

O₃(g) + NO(g) → O₂(g) + NO₂(g)   (1)

The reaction rate of equation (1) is given by:

rate = k*[O_{3}][NO]     (2)

<u>We have:</u>

k: is the rate constant of reaction = 3.91x10⁶ M⁻¹.s⁻¹

[O₃]₀ = 2.35x10⁻⁶ M

[NO]₀ = 7.74x10⁻⁵ M

Hence, to find the inital reacion rate we will use equation (2):

rate = k*[O_{3}]_{0}[NO]_{0} = 3.91 \cdot 10^{6} M^{-1}s^{-1}*2.35\cdot 10^{-6} M*7.74 \cdot 10^{-5} M = 7.11 \cdot 10^{-4} M/s  

Therefore, the inital reaction rate is 7.11x10⁻⁴ M/s

(b) The number of moles of NO₂(g) produced per hour per liter of air is:

t = 1 h

V = 1 L

\frac{\Delta[NO_{2}]}{\Delta t} = rate

\frac{\Delta[NO_{2}]}{\Delta t} = 7.11 \cdot 10^{-4} M/s*\frac{3600 s}{1 h} = 2.56 mol.L^{-1}.h{-1}

Hence, the number of moles of NO₂(g) produced per hour per liter of air is 2.56 mol.L⁻¹.h⁻¹

I hope it helps you!                                

5 0
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