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sattari [20]
3 years ago
9

Need help Again pls help thx

Mathematics
2 answers:
Virty [35]3 years ago
5 0
The correct answer is 4/7 All I had to do was cross reduce
zimovet [89]3 years ago
3 0

The answer is in the photo along with the work ;)

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Assume the number of pounds of chocolate consumed in a year is equally likely between 20 and 100 pounds. what is the probability
kramer
Because the probability is uniform (equally likely) between 20 and 100 pounds, the probability distribution is uniform between 80 and 100 pounds, with the value 1/(100-20) = 1/80 chocolates/pound.

Let x =  random variable that represents pounds of chocolate consumed.
Therefore
P(x < 60) = (60 - 20)*(1/80) = 1/2.

Answer: The probability is 1/2.
4 0
3 years ago
3 a + b equals negative 1, negative 3 a plus b equals 5
Tcecarenko [31]
What am I supposed to be solving for?
3 0
4 years ago
How.to find area of parallelogram with missing height?
nlexa [21]

Answer:

You divide the area by the number you already have.

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Plz help ty :)))))))))
Neporo4naja [7]
3x - 3y = -12      ------------- (1)
7x + 2y = -19     --------------(2)

(1) x 2 : 6x - 6y = - 24       ----------- (1a)
(2) x 3 : 21x + 6y = -57     ----------- (2a)

(1a) + (2a) : 27x =  - 81
                        x = - 3

Sub x = -3 into (1) :  3(-3) - 3y = - 12 
                                               y = - 12  + 9
                                               y = - 3

Answer( -3, -3)


3 0
3 years ago
The serum cholesterol levels for men in one age group are normally distributed with a mean of 178.1 and a standard deviation of
Xelga [282]

Answer:

  the levels are 123.5 and 232.7 mg/mL

Step-by-step explanation:

The inverse normal function is used to find limit values from an area (probability).

Your calculator can show these values to you. (see attached)

The top 9% are above 232.7 mg/mL.

The bottom 9% are below 123.5 mg/mL.

__

A suitable calculator can evaluate the inverse normal function to find the x-value corresponding to some area, mean, and standard deviation. For the level that separates the bottom 9% from the rest of the area, we use an area value of 0.09. The mean and standard deviation values are those provided in the problem statement.

For the level that separates the top 9% from the rest of the area, we use an area value of 1 -0.09 = 0.91.

__

The second attachment shows an online calculator that can give the limits on the middle 0.91 -0.09 = 0.88 of the area under the probability curve.

_____

<em>Additional comment</em>

An app version of an approximation to a TI-Nspire calculator is shown in the first attachment. The invNorm function is found at the Distr key (2nd VARS).

6 0
3 years ago
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