Answer:
62.29%
Step-by-step explanation:
The probability of Aya being offered a coupon on at least one of the six days she visits the website is 100% minus the probability that she is not offered a coupon on any of the six days, which is described by a binomial probability with zero successes in six trials with a probability of succes p = 0.15.
The probability that Aya will be offered a coupon on at least one of the days she visits the website is 62.29%.
Considering the Central Limit Theorem, we have that:
a) The probability cannot be calculated, as the underlying distribution is not normal and the sample size is less than 30.
b) The probability can be calculated, as the sample size is greater than 30.
<h3>What does the Central Limit Theorem state?</h3>It states that the sampling distribution of sample means of size n is approximately normal has standard deviation , as long as the underlying distribution is normal or the sample size is greater than 30.
In this problem, the underlying distribution is skewed right, that is, not normal, hence:
More can be learned about the Central Limit Theorem at brainly.com/question/16695444
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Answer: The required probability of having 6th girl is 0.5.
Step-by-step explanation: Given that boys and girls are equally likely.
We are to find the probability of a couple having a baby girl when their sixth child is born, given that the first five children were all girls.
Since the events of having a boy and a girl are independent of each other, so
the probability of having 6th girl dose not depend on the birth of the first five girls.
We know that there are only two possible cases (either a boy or girl will born).
So, sample space, S = {G, B} and the event E of having a girl is, E = {G}.
That is, n(S) = 2 and n(E) = 1.
Therefore, the probability of event E is given by
Thus, the required probability of having 6th girl is 0.5.
