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zalisa [80]
2 years ago
9

How much does REAL carbon fiber cost ? lets say as big as a piece of paper

Chemistry
1 answer:
coldgirl [10]2 years ago
8 0

Answer:

Today, the average total production cost of “standard modulus” carbon fiber is in the range of $7-9 per pound.

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For a certain reaction, Kc = 2.76×103 and kf= 6.54×10−4 M−2⋅s−1 . Calculate the value of the reverse rate constant, kr, given th
riadik2000 [5.3K]

Answer:

2.37x10⁻⁷ M⁻².s⁻¹

Explanation:

For a generic reversible reaction:

A + B ⇄ C + D

Kf is the constant of the formation of the products (C and D), Kr is the constant of the formation of the reactants (A and B), and Kc is the general equilibrium constant, which is:

Kc = Kf/Kr

2.76x10³ = 6.54x10⁻⁴/Kr

Kr = 6.54x10⁻⁴/2.76x10³

Kr =  2.37x10⁻⁷ M⁻².s⁻¹

5 0
3 years ago
The atomic mass of an element is equal to the:
stich3 [128]
The atomic mass is equal to the number of neutrons, plus the number of protons, in the nucleus of the atom
4 0
3 years ago
Read 2 more answers
Determine the number of molecules in 3.79 kilograms of the fictional compound Cs7(Cr5O3)4. Include the units, but do not write t
Karo-lina-s [1.5K]

Answer:

1.0555 * 10^24 molecules

Explanation:

Number of molecules = ?

Mass = 3.79  Kg = 3790 g

Molar mass of Cs7(Cr5O3)4 = 2162.25 g/mol

Number of moles = Mass / Molar mass

Number of moles = 3790 g / 2162.25 g/mol

Number of moles = 1.7528 mol

1 mol = 6.022 * 10^23 molecules

1.7528 mol = x

solving for x;

x = 6.022 * 10^23 *  1.7528

x = 1.0555 * 10^24 molecules

7 0
2 years ago
What is a thermograph
abruzzese [7]

I think it is D the last choice

5 0
3 years ago
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(b) Data has been collected to show that at a given wavelength in a 1 cm pathlength cell, Beer's Law for the absorbance of Co2+
OlgaM077 [116]

Answer : The concentration of a solution with an absorbance of 0.460 is, 0.177 M

Explanation :

Using Beer-Lambert's law :

A=\epsilon \times C\times l

where,

A = absorbance of solution

C = concentration of solution

l = path length

\epsilon = molar absorptivity coefficient

From this we conclude that absorbance of solution is directly proportional to the concentration of solution at constant path length.

Thus, the relation between absorbance and concentration of solution will be:

\frac{A_1}{A_2}=\frac{C_1}{C_2}

Given:

A_1 = 0.350

A_2 = 0.460

C_1 = 0.135 M

C_2 = ?

Now put all the given values in the above formula, we get:

\frac{0.350}{0.460}=\frac{0.135}{C_2}

C_1=0.177M

Therefore, the concentration of a solution with an absorbance of 0.460 is, 0.177 M

3 0
3 years ago
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