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2 years ago

How does the smell of food being cooked spread so fast ???

Chemistry

2 answers:

natta225 [31]2 years ago

6 0

Answer:

smell of cooked food spread fast bc when something is heated up, the kinetic energy of the molecules/particles increases and some of them even mix with the air and moves around. the first answer is also correct (i just explained it more detaily)

so, this is the reason :)

mark as brainliest dagini ;)

sladkih [1.3K]2 years ago

5 0

Answer:

When we cook food in the kitchen, that's the region of higher concentration of the smell. By diffusion, the smell spreads to the whole room and thereby whole house, so anyone standing at a distance, can smell it.

You might be interested in

A chemical that helps plant cells grow larger is a what?

RUDIKE [14]

Chlorophyll is the chemical that helps plant cells grow

3 0

2 years ago

For the separation of components of a mixture, we are following different methods. What is the condition in which the process of

soldier1979 [14.2K]

Answer:

The mixture 1/ must be homogeneous where there is one or more dissolved salts; 2/ should only contain one liquid component.

Explanation:

This method drives off the liquid components from the solid components. The process typically involves heating the mixture until no more liquid remains. Prior to using this method, the mixture should only contain one liquid component, unless it is not important to isolate the liquid components. This is because all liquid components will evaporate over time. This method is suitable to separate a soluble solid from a liquid.

Note : In many parts of the world, table salt is obtained from the evaporation of sea water. The heat for the process comes from the sun.

...

Hope this answer can help you. Have a nice day!

4 0

3 years ago

If the caffeine concentration in a particular brand of soda is 2.85 mg/oz, drinking how many cans of soda would be lethal? Assum

alina1380 [7]

Answer:

2,375 cans

Explanation:

The strategy here is to use the information given to calculate the lethal dosage contained in the number of cans we will compute.

We know the lethal dosage is

Ld = 10.0 g caffeine

and we also know that the oncentration of caffeine is:

2.85 mg/ oz

So our problem simplifies to calculate how many oz will contain the lethal dose, and then given the ounces per can determine how many cans are required.

First convert the lethal dose in grams to mg:

Ld =( 10 g x 1000 mg ) = 10,000 mg caffeine

10,000 mg x ( 1 Oz / 2.85 mg ) = 28,500 oz

28500 oz x ( 1 can/12 oz ) = 2,375 cans

We could also have calculated it in one step using conversion factors:

Number of cans = 10000 mg x 1 oz/ 2.85 mg x 1 can / oz = 2,375 cans

7 0

3 years ago

a chemist adds of a calcium bromide solution to a reaction flask. calculate the mass in grams of calcium bromide the chemist has

mestny [16]

The mass of Calcium bromide added in the flask is 29.7 g.

<h3>What is Molarity? </h3>

Molarity is defined as the ratio of number of moles od solute to the number of volume of solution in litres.

Molarity = number of moles/ volume

<h3>Calculation of Moles</h3>

Number of moles = Molarity × volume

Given,

Molarity of Calcium bromide = 0.363 M

Volume of Calcium bromide = 410 mL

= 0.410L

By substituting all the value, we get

Number of moles = 0.363 × 0.410

= 0.148 mol

As we know that,

Molar mass of Calcium bromide = 199.89 g

Mole is defined as the given mass of substance to the molar mass of substance.

Given mass = Moles × Molar mass

= 0.148 × 199.89

= 29.75 g

= 29.7 g (significant digit)

Thus, we calculated that the mass of Calcium bromide added in the flask is 29.7 g.

learn more about Molarity:

brainly.com/question/19517011

#SPJ4

DISCLAIMER:

The above question is incomplete. Below is the complete question

A chemist adds 410.0mL of a 0.363 M calcium bromide solution to a reaction flask. calculate the mass in grams of calcium bromide the chemist has added to the flask. round your answer to 3 significant digits.

4 0

1 year ago

The equilibrium constant for the reaction of carbon monoxide with water is 1.845. if 1.00 mol of each reactant is placed in a 2.

SpyIntel [72]

[CO] = 1 mol / 2L = 0.5 M

[
According to the equation:

and by using the ICE table:

CO(g) + H2O(g) ↔ CO2(g) + H2(g)

initial 0.5 0.5 0 0

change -X -X +X +X

Equ (0.5-X) (0.5-X) X X

when Kc = X^2 * (0.5-X)^2

by substitution:

1.845 = X^2 * (0.5-X)^2 by solving for X

∴X = 0.26

∴ [CO2] = X = 0.26

4 0

2 years ago