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Answer:
The diameter of wire should be m
Explanation:
Given:
Current density
Current A
From the formula of current density,
Where area of cylindrical wire =
m
For finding the diameter of wire,
m
Therefore, the diameter of wire should be m
Answer:
W = ½ m v²
Explanation:
In this exercise we must solve it in parts, in a first part we use the conservation of the moment to find the speed after the separation
We define the system formed by the two parts of the rocket, therefore the forces during internal separation and the moment are conserved
initial instant. before separation
p₀ = m v
final attempt. after separation
= m /2 0 + m /2 v_{f}
p₀ = p_{f}
m v = m /2
v_{f}= 2 v
this is the speed of the second part of the ship
now we can use the relation of work and energy, which establishes that the work is initial to the variation of the kinetic energy of the body
initial energy
K₀ = ½ m v²
final energy
= ½ m/2 0 + ½ m/2 v_{f}²
K_{f} = ¼ m (2v)²
K_{f} = m v²
the expression for work is
W = ΔK = K_{f} - K₀
W = m v² - ½ m v²
W = ½ m v²
- The length of its image =
Given,
length of object,
We know, for flat refracting surface,
Image distance = object distance
So,
magnification is =
length of the image,
Here, negative sign means inverted image.
For more information on refraction, visit