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den301095 [7]
3 years ago
11

Need help ASAP shoving brainlest plsssss

Physics
1 answer:
seraphim [82]3 years ago
3 0
The answer for this would be B!!
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The voltage across the terminals of an ac power supply varies with time according to V=V0cos(t). The voltage amplitude is V0 = 4
kirza4 [7]

Answer:

A) V_rms = 29 V

B) Vav = 0 V

Explanation:

A) We are told that;

V = V_o cos ωt

voltage amplitude; V = V_o = 41.0V

Now, the formula for the root-mean-square potential difference Vrms is given as;

V_rms = V/√2

Thus plugging in relevant values, we have;

V_rms = 41/√2

V_rms = 29 V

B) Due to the fact that the voltage is sinusoidal from the given V = V_o cos ωt, we can say that the average potential difference Vav between the two terminals of the power supply would be zero.

Thus; Vav = 0 V

5 0
3 years ago
Explain using physics vocabulary WHY the volume increases as the temperature increases.
Sveta_85 [38]

Answer:

P V = n R T      ideal gas equation

V = k T     where k = a constant and equals k = n R / P

V is proportional to T when other factors are constant

4 0
2 years ago
How to do this question?​
Zigmanuir [339]

Answer:

First.

  • Find double diffrenciation of all equation
  • Then put the value of t in the differenciated equations
3 0
3 years ago
Calculate the kinetic energy in joules of a 1,500 kg car that is moving at a speed of 42 km/h
Rzqust [24]
Data:
KE (Kinetic Energy) = ? (Joule)
m (mass) = 1500 Kg 
v (speed) = 42 Km/h
converting to m/s (42 / 3.6), we have: v (speed) = 11.6 m/s

Formula:
K_{E} =   \frac{1}{2} m*v^2

Solving:
K_{E} = \frac{1}{2} m*v^2
K_{E} =  \frac{1}{2} *1500*(11.6)^2
K_{E} = \frac{1}{2} *1500*134.56
K_{E} =  \frac{201840}{2}
\boxed{\boxed{K_{E} = 100920\:Joule}}\end{array}}\qquad\quad\checkmark





4 0
3 years ago
What are the five advantages of using machine and tools in our daily life?​
daser333 [38]

Answer:

it makes our work easy and

time saving

it multiply our force applied

it complete our work with high efficiency

by using this,less effort is required for the work.

7 0
2 years ago
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