2. After you cross the finish line, you slow
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Answer:
Therefore,
The potential (in V) near its surface is 186.13 Volt.
Explanation:
Given:
Diameter of sphere,
d= 0.29 cm
Charge ,
To Find:
Electric potential , V = ?
Solution:
Electric Potential at point surface is given as,
Where,
V= Electric potential,
ε0 = permeability free space = 8.85 × 10–12 F/m
Q = Charge
r = Radius
Substituting the values we get
Therefore,
The potential (in V) near its surface is 186.13 Volt.