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xenn [34]
3 years ago
12

| Find the quadratic polynomial whose Sum and products of zeros are 21/8 and 5/16

Mathematics
1 answer:
tatuchka [14]3 years ago
8 0

Answer:

16x^{2} -42x+5

Step-by-step explanation:

Sum of its zeroes=\alpha +\beta =\frac{21}{8} \\

Product of its zeroes=\alpha \beta=\frac{5}{16}

Formula to form a quadratic polynomial:

p(x)=k[x^{2} -(\alpha +\beta )x+\alpha \beta ]

p(x)=k[x^{2} -(\frac{21}{8} )x+\frac{5}{16}]

p(x)=16[x^{2} -(\frac{21}{8} )x+\frac{5}{16}]

p(x)=[16x^{2} -42x+5]

The quadratic polyniomial is 16x^{2}-42x+5

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In 2003, the population of an African country was about 13.1 million people, which is 2 million more than 3 times the population
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If I had a large square with 12 small squares shaded what percentage of the square is shaded
zhuklara [117]

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1
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4 years ago
Assume that the national credit card interest rate is 12.83 percent. A study of 62 college students finds that their average int
meriva

Answer:

b)  95 percent confidence interval for this single-sample t test

[11.64, 16.36]

Step-by-step explanation:

Explanation:-

Given data  a study of 62 college students finds that their average interest rate is 14 percent with a standard deviation of 9.3 percent.

Sample size 'n' =62

sample mean x⁻ = 14  

sample standard deviation 'S' = 9.3

<u>95 percent confidence interval for this single-sample t test</u>

The values are (x^{-} - t_{0.05} \frac{S}{\sqrt{n} } ,x^{-}+t_{0.05}\frac{S}{\sqrt{n} })  the <u>95 percent confidence interval for the population mean  'μ'</u>

Degrees of freedom γ=n-1=62-1=61

t₀.₀₅ = 1.9996 at 61 degrees of freedom

(14 - 1.9996\frac{9.3}{\sqrt{62} } ,14+1.9996\frac{9.3}{\sqrt{62} })

(14-2.361 , 14 + 2.361)

[(11.64 , 16.36]

<u>Conclusion:-</u>

95 percent confidence interval for this single-sample t test

[11.64, 16.36]

<u></u>

6 0
3 years ago
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