Answer: see proof below
<u>Step-by-step explanation:</u>
Use the Sum & Difference Identity: cos (A + B) = cos A · cos B - sin A · sin B
Recall the following from Unit Circle: cos (π/2) = 0, sin (π/2) = 1
cos (π) = -1, sin (π) = 0
Use the Quotient Identity:
<u>Proof LHS → RHS:</u>
Quotient: tan x
LHS = RHS
Answer:
<em>y = 3x + 5</em>
Step-by-step explanation:
y = mx + b (slope-intercept form)
( ,
)
( ,
)
Slope m =
y - = m( x -
) (point-slope form of linear equation)
~~~~~~~~~~~~~~~
We have been given that a right △ABC is inscribed in circle k(O, r).
m∠C = 90°, AC = 18 cm, m∠B = 30°. We are asked to find the radius of the circle.
First of all, we will draw a diagram that represent the given scenario.
We can see from the attached file that AB is diameter of circle O and it a hypotenuse of triangle ABC.
We will use sine to find side AB.
Wee know that radius is half the diameter, so radius of given circle would be half of the 36 that is .
Therefore, the radius of given circle would be 18 cm.
