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ololo11 [35]
4 years ago
15

Which of the following is soluble in water (A-sand) (B-pepper) (C- oil) (D-honey)​

Chemistry
2 answers:
iren2701 [21]4 years ago
8 0

Answer:

D- Honey

Explanation:

Honey is naturally water-soluble and oil is non polar meaning it is not attracted to water. Sand and pepper are insoluble.

mina [271]4 years ago
6 0

Answer:

The correct answer is (D.)

Explanation:

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Calculate the molar concentration of the Br⁻ ions in 0.51 M MgBr2(aq), assuming that the dissolved substance dissociates complet
Y_Kistochka [10]
MgBr2(aq) is an ionic compound which will have the releasing of 2 Br⁻ ions ions in water for every molecule of MgBr2 that dissolves.
MgBr2(s) --> Mg+(aq) + 2 Br⁻(aq)
            [Br⁻] = 0.51 mol MgBr2/1L × 2 mol Br⁻ / 1 mol MgBr2 = 1.0 M
The answer to this question is [Br⁻] = 1.0 M
6 0
3 years ago
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2 years ago
50.0 g of NaNO3 are dissolved into enough water to make 250 mL of solution. What is the molarity of this solution?
d1i1m1o1n [39]

Answer:

2.35 M

Explanation:

Molarity is mol/L of solution. We have to convert the g to mol and the mL to L. G to mol uses the molar mass of the compound. The molar mass of NaNO₃ is 85.00g/mol.

50.0gNaNO3*\frac{1molNaNO3}{85.00gNaNO3} = 0.588molNaNO3

Then you have to convert mL to L.

250mL*\frac{1L}{1000mL} = 0.250L

Now divide the mol by the L.

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Round to the smallest number of significant figures = 2.35M

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