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Rzqust [24]
3 years ago
10

I need helppppppppppp

Chemistry
2 answers:
agasfer [191]3 years ago
8 0

Answer:

option c hope it will help u

kicyunya [14]3 years ago
7 0

A B C

a. Mg(12) 2.8.2 -2e- = Mg2+

b. S(16) 2.8.6 +2e- = S2-

c. MgS

d. No, because it is neutral

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After severe dust storms in the 1930s, practices were put in place to reduce soil erosion. Which
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Answer: Farmers were paid to practice soil-conserving techniques like crop rotation and terracing

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read about it here: https://www.pbs.org/wgbh/americanexperience/features/dust-bowl-surviving-dust-bowl/

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3 years ago
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H2 H2O H2O2 CH4 All four examples represent
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Calculate the molarity of a solution with 114.95 grams of sodium dissolved in 2 L of water. ​
koban [17]

Answer:

The molarity of a solution is 2.5 M

Explanation:

Molarity is a concentration unit that describes how much of a solution is dissolved in solution.

Molarity of a solution can found by using the formula,

Molarity (M) = (moles of solute)/(Liters of Solution).

Given, mass of Sodium = 114.95 grams.

Volume of water = 2 L.

Here, Sodium is solute as it is dissolved in water, which is the solvent.

Moles of Sodium(solute) can be found by using the formula,

Number of Moles = mass/Molecular weight.

mass of Sodium = 114.95 grams.

Molecular weight = 22.989 grams

Number of Moles of Sodium(solute) =114.95/22.989 = 5.

Substituting the values in the formula, we get,

M = 5/2 = 2.5 M

3 0
3 years ago
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Aluminum foil I think but if not goodluck :)
5 0
2 years ago
Read 2 more answers
Write the balanced standard combustion reaction for the c5h7on3s2
AlexFokin [52]

Answer:

4C5H7ON3S2 + 25O2 —> 20CO2 + 14H2O + 6N2 + 4S2

Explanation:

When C5H7ON3S2 under go Combustion, the following are obtained as illustrated below:

C5H7ON3S2 + O2 —> CO2 + H2O + N2 + S2

Now, let us balance the equation. This is illustrated below:

C5H7ON3S2 + O2 —> CO2 + H2O + N2 + S2

There are 3 atoms of N on the left side and 2 atoms on the right side. It can be balance by putting 4 in front of C5H7ON3S2 and 6 in front of N2 as shown below:

4C5H7ON3S2 + O2 —> CO2 + H2O + 6N2 + S2

There are 20 atoms of C on the left side and 1 atom on the right side. It can be balance by putting 20 in front of CO2 as shown below:

4C5H7ON3S2 + O2 —> 20CO2 + H2O + 6N2 + S2

There are 28 atoms on H on the left side and 2 atoms on the right side. It can be balance by putting 14 in front of H2O as shown below:

4C5H7ON3S2 + O2 —> 20CO2 + 14H2O + 6N2 + S2

There are 8 atoms of S on the left side and 2 atoms on the right side. It can be balance by putting 4 in front of S2 as shown below:

4C5H7ON3S2 + O2 —> 20CO2 + 14H2O + 6N2 + 4S2

Now, there are a total of 54 atoms of O on the right side and 6 atoms on the left side

It can be balance by putting 25 in front of O2 as shown below:

4C5H7ON3S2 + 25O2 —> 20CO2 + 14H2O + 6N2 + 4S2

Now, we can see that the equation is balanced.

4 0
3 years ago
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