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Oksi-84 [34.3K]
3 years ago
6

If the pOH of a cesium hydroxide solution is known to be 4.00. what is the (OH)? *Please round your answer to the appropriate nu

mber of significant figures. Your answer can be in standard notation o "e" in place of x10.* 1​
Chemistry
1 answer:
Snowcat [4.5K]3 years ago
4 0

Answer:

i going to be aniston i would say take a gess

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propane is a hydrocarbon, a compound composed only of carbon and hydrogen. it is 81.82% carbon and 18.18% hydrogen. what is the
scoundrel [369]

Firstly need to determine the empirical formula of the hydrocarbon. Empirical formula is the simplest whole number ratio of components of the compound. Molecular formula  is the actual composition of the components in the compound.

percentage of C - 82.66%

percentage of H - (100-82.66) = 17.34 %

in 100 g of compound ;

mass of C - 82.66 g

mass of H - 17.34 g

                                 C                               H

mass in 100 g        82.66 g                      17.34 g

molar mass           12 g/mol                      1 g/mol

number of moles    6.88 mol                     17.34 mol

(mass/molar mass)

divide the number of moles by least number of moles (6.88 mol)

                               6.88 mol/6.88             17.34/6.88

                                1                                 2.52

multiply these by 2 to get a whole number 

C - 1x 2 = 2

H - 2.52 x 2 = 5.04

round off to nearest whole number 

C - 2

H - 5

ratio of C to H is 2:5

empirical formula - C₂H₅

empirical formula mass = 12 g/mol x 2 + 5 * 1 g/mol = 29 g

next have to find how many empirical units are there in the molecular unit 

molecular unit mass = 58.12 g

empirical unit = 29 g

then number of empirical units = 58.12 / 29 = 2

rounded off , number of empirical units = 2

(C₂H₅) * 2 units

molecular formula = C₄H₁₀

Explanation:

8 0
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