The position of the 7 is in the ten thousandths place.
Our current list has 11!/2!11!/2! arrangements which we must divide into equivalence classes just as before, only this time the classes contain arrangements where only the two As are arranged, following this logic requires us to divide by arrangement of the 2 As giving (11!/2!)/2!=11!/(2!2)(11!/2!)/2!=11!/(2!2).
Repeating the process one last time for equivalence classes for arrangements of only T's leads us to divide the list once again by 2
Answer:
Largest volume in terms of r = 4r^3π/ 3√3 or you could write it as 4√3r^3π/9.
Step-by-step explanation:



To multiply powers of the same base, add their exponents.

Add 5 and 2 to get 7.

- The first option <em><u>n⁷</u></em><em><u> </u></em>is the correct answer.