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3 years ago

Which contains more molecules: 340g of NH3 or 90g of H2O show your working!!

Chemistry

2 answers:

elena-14-01-66 [18.8K]3 years ago

8 0

Answer:

Explanation:

The atomic weight of H2O is 18, 18g of water is 1 mole of H2O. 1 mole of any substance contains 6.023 x 10 23 number of atoms. The atomic weight of NH3 is 17 so 17g of NH3 contains 6.023 x 10 23 atoms. 340g of NH3 contains 20 moles of NH3.

90g of H2O is 5 moles of H2O, so there are 4 times as many molecules of NH3 as there are molecules of H2O.

The answer is NH3

Hope this helps

Shtirlitz [24]3 years ago

6 0

Answer:

atomic mass ( N =14 , H = 1×3 that means 14+3=17

340gram×17gram / mole

=5780mole

atomic mass ( H= 1×2 ,O= 16 =16+2 =18

90gram×18gram /mole

=1620mole

I think 340g ammonia (NH3)

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What is the molar mass of water in the hydrate? FeSO4 • 7H2O

Rainbow [258]

M=7M(H₂O)

M=7*18.015 g/mol = 126.105 g/mol

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4 years ago

How many grams of Mg are needed to produce 224 g of MgO in the complete reaction of Mg

zmey [24]

Answer:

134.4 g of Mg

Explanation:

reaction:

2Mg + O2 ➡️ 2MgO

1) find the mol of MgO

mol = mass / molar mass

mass = 224 g

molar mass = 24+16 = 40

mol = 224 / 40

= 5.6 moles

2 mol = 5.6 moles

2) find the mass of Mg

mass = mol × molar mass

mol = 5.6

molar mass = 24

mass = 5.6 × 24

= 134.4 g

7 0

3 years ago

Convert 1.7 Kg to cg

Kipish [7]

To answer this lets first see how much 1 kg is equal to in cg.

1 kg = 100000 cg

Now lets multiply:-

100000 × 1.7 = 170000

So, 1.7 kg = 170000 cg

Hope I helped ya!!!

4 0

4 years ago

Read 2 more answers

What is the mass of 1.82 moles of Lithium carbonate?

frutty [35]

Answer:

244.76

Explanation:

The weight of grams by 1.82 moles of lithium carbonate would be: 134.481438 So we need to use this equation to find mass by grams m × g = ms Where m is for moles, g for grams, and ms for mass. So now we need use this equation: 1.82 × 134.481438 = ? 1.82 × 134.481438 = 244.75621716 244.75621716, rounded-up (to the nearest-tenths place) is 244.76. So now you have it! The mass of 1.82 moles of lithium carbonate is 244.76!

7 0

3 years ago

During the following chemical reaction, 46.3 grams of C3H6O react with 73.2 grams of O2

ra1l [238]

Answer:

a) O2 is the limiting reactant

b) 75.70 grams CO2 (theoretical yield)

c) There remains 12.81 grams of C3H6O

d) The actual yield CO2 is 34.29 grams

Explanation:

Step 1: Data given

Mass of C3H6O = 46.3 grams

Mass of O2 = 73.2 grams

Molar mass of C3H6O = 58.08 g/mol

Molar mass of O2 = 32 g/mol

Step 2: The balanced equation

C3H6O + 4O2 → 3 CO2 + 3H2O

Step 3: Calculate moles C3H6O

Moles C3H6O = mass C3H6O / molar mass C3H6O

Moles C3H6O = 46.3 grams / 58.08 g/mol

Moles C3H6O = 0.793 moles

Step 4: Calculate moles O2

Moles O2 = 73.2 grams / 32 g/mol

Moles O2 = 2.29 moles

Step 5: Calculate limiting reactant

For 1 mol C3H6O we need 4 moles of O2 to produce 3 moles CO2 and 3 moles H2O

O2 is the limiting reactant. It will completely be consumed. (2.29 moles).

C3H6O is in excess. There will react 2.29/4 = 0.5725 moles C3H6O

There will remain 0.793 - 0.5725 = 0.2205 moles C3H6O

This is 0.2205 moles * 58.08 g/mol = 12.81 grams

Step 6: Calculate moles of CO2

For 1 mol C3H6O we need 4 moles of O2 to produce 3 moles CO2 and 3 moles H2O

For 2.29 moles O2 we need 3/4 * 2.29 = 1.72 moles CO2

This is 1,72 moles * 44.01 g/mol = 75.70 grams CO2

Step 7: Calculate actual yield

% yield = 45.3 % = 0.453 = (actual yield / theoretical yield)

actual yield = 0.453 * 75.70 = 34.29 grams

3 0

3 years ago