Answer: The final temperature of both substances at thermal equilibrium is 301.0 K
Explanation:
As we know that,
![m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]](https://tex.z-dn.net/?f=m_1%5Ctimes%20c_1%5Ctimes%20%28T_%7Bfinal%7D-T_1%29%3D-%5Bm_2%5Ctimes%20c_2%5Ctimes%20%28T_%7Bfinal%7D-T_2%29%5D)
.................(1)
where,
q = heat absorbed or released
= mass of gold = 31.5 g
= mass of water = 63.4 g
= final temperature = ?
= temperature of gold = 
= temperature of water = 
= specific heat of gold = 
= specific heat of water= 
Now put all the given values in equation (1), we get
![-31.5\times 0.129\times (T_{final}-342.4)=[63.4\times 4.184\times (T_{final}-300.4)]](https://tex.z-dn.net/?f=-31.5%5Ctimes%200.129%5Ctimes%20%28T_%7Bfinal%7D-342.4%29%3D%5B63.4%5Ctimes%204.184%5Ctimes%20%28T_%7Bfinal%7D-300.4%29%5D)
The final temperature of both substances at thermal equilibrium is 301.0 K
Answer:
Hello! Your answer would be, D) HCI
Explanation:
Hope I helped! Ask me anything if you have any questions. Brainiest plz!♥ Hope you make a 100%. Have a nice morning! -Amelia♥
The conversion factor for volume at STP is
or \frac {22.4L}{1mol}. Since we want volume, we would use \frac {22.4L}{1mol}. We conclude with the following calculations:
The answer is 44.8L Cl2
Answer:
2.5 mol/L
Explanation:
We'll begin by calculating the number of mole in 7 g of KOH. This can be obtained as follow:
Mass of KOH = 7 g
Molar mass of KOH = 39 + 16 + 1
= 56 g/mol
Mole of KOH =?
Mole = mass /molar mass
Mole of KOH = 7 / 56
Mole of KOH = 0.125 mole
Next, we shall convert 50 mL to L. This can be obtained as follow:
1000 mL = 1 L
Therefore,
50 mL = 50 mL × 1 L / 1000 mL
50 mL = 0.05 L
Finally, we shall determine the molarity of the KOH solution. This can be obtained as follow:
Mole of KOH = 0.125 mole
Volume = 0.05 L
Molarity of KOH =?
Molarity = mole / Volume
Molarity of KOH = 0.125 / 0.05
Molarity of KOH = 2.5 mol/L
Thus, the molarity of the KOH solution is 2.5 mol/L
