Answer:
C. Electron is the correct answer
Answer is: HCl (hydrochloric acid) <span>will have the largest amount of conjugate base.
Hydrochloric acid is the strongest acid present in this question, because it has largest Ka value:
pKa(HCl) = -8.
Ka(HCl) = 10</span>∧(-pKa).
Ka(HCl) = 10⁸.
Chemical dissotiation of hydrochloric acid:
HCl(aq) → H⁺(aq) + Cl⁻(aq).
Ka(HCl) = [H⁺]·[Cl⁻] / [HCl].
Concentration of Cl⁻ ions (conjugate base of hydrochloric acid) is very high.
You need to know the following equations:
pH=-log[H⁺]
pOH=-log[OH⁻]
pH+pOH=14
then you can find the pH by using pH=-log(1×10⁻¹)
pH=1
then you can find pOH by doing pOH=14-1
pOH=13
then you can find [OH] by using [OH⁻]=10^(-pOH)
[OH⁻]=1×10⁻¹³mol/L
You could also use the equation Kw=[OH⁻][H⁺] where Kw=10⁻¹⁴
10⁻¹⁴/10⁻¹=10⁻¹³mol/L
I hope this helps. Let me know if anything is unclear.
Answer:
7
Explanation:
This question is a neutralization reaction.
50 ml of 0.125 M of KOH = (50 x 0.125) = 6.25 ml
In this same way, 50 ml of 0.125M of HCl = 50x0.125
= 6.25 ml
Then KOH is going to neutralise the HCl fully suvh that the pH of the medium is going to be 7
(H+) + (OH-) = H2O
Then Kw = [H=][OH-]
= [H+]² = 10^-14
Such that [H+] = 10^-7
The pH would be = -log [H+]
= -log[10^-7]
When inputted on a calculator this gives us 7
= 7
This is our answer
Yes that is true all cells have cytoplasm and cell membrane! hope this helps! ;D