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9966 [12]
3 years ago
12

Calculate the number of molecules in 64.5 grams of Nitrogen monoxide, NO

Chemistry
1 answer:
Alinara [238K]3 years ago
7 0

Answer:

N=9.933×10^23

Explanation:

n =  \frac{m}{mr}

N=n×la

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Cuántos gramos de hidróxido de sodio (NaOH) se debe de agregar a un litro de agua para obtener una disolución al 25% en masa
Tamiku [17]

Answer:

= 250 gramos

Explanation:

No ha preguntado sobre peso / peso o peso / volumen.

Para w / v:

Simplemente tome el 25% de 1000 y luego agréguelo en 1L de agua

La masa de NaOH necesaria es de 250 g.

Para w / w:

250 gramos de NaOH y 750 g de agua, hará que la solución sea 1L.

5 0
3 years ago
Determina el numero de masa para el paladio en la siguiente tabla:*
Damm [24]

The concept of atomic masses we can find that the correct answer is:

       c) 101

The atomic mass or mass number of an element is the sum of its protons plus the neutrons that are in the atomic nucleus, the electrons are not taken into account because they have a mass much lower than the masses of protons and neutrons.

   

In the table they indicate that there are 46 protons and 55 neutrons, therefore

          M = #_ {protons} + #_ {neutrons}

          M = 46 +55

          M = 101

In conclusion using the concept of atomic masses we find that the correct answer is:

c) 101

Learn more about atomic mass here:

brainly.com/question/1317964

5 0
3 years ago
What describes a mixture
kirill [66]

Answer:

a mixture is a material made up of two or more different substances which are physically combined.

4 0
3 years ago
Please help me dont just use me for points
JulijaS [17]

Answer:

It's B

Explanation:

A is going to evaporate more quickly causing it to push through the tube to beaker B.

4 0
3 years ago
If 200 grams of water is to be heated from 24.0oC to 100.0oC to make a cup of tea, how much heat must be added?
aksik [14]
According to this formula:

Q = M*C*ΔT 

when we have M ( the mass of water) = 200 g 

and C ( specific heat capacity ) of water = 4.18 J/gC

ΔT (the difference in temperature) = Tf - Ti 
     
                                                          = 100 - 24

                                                          = 76°C

So by substitution:


Q = 200 g * 4.18 J/gC * 76 °C

   = 63536 J 

 ∴ the amount of heat which be added and absorbed to raise the temp from 24°C to 100°C is = 63536 J


3 0
3 years ago
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