8.24621 is the distance between the points
Step-by-step explanation:
1 km = 1000 m
(hence the term "kilo" which means 1000).
so. he runs 1000 m at the rate of 3 minutes per km, that means 3 minutes per 1000 m.
now, we can see the solution already with our eyes.
but let's do it formally :
the rate or ratio between time and distance must be the same for the same speed.
so,
3 min / 1000 m = x min / 500 m
500 m × 3 min / 1000 m = x min
1/2 × 3 min = x min
3/2 = 1.5 min = x min
so, it takes him 1.5 minutes (90 seconds) to run 500 m.
I agree with you because theta could be acute or obtuse, and if obtuse, negative value.
Easy peasy
just subsitute I(x) for the x in the h(x) so
h(I(s))=-(2s+3)^2-4
distribute and simplify
h(I(s))=-(4s^2+12s+9)-4
h(I(s))=-4s^2-12s-9-4
h(I(s))=-4s^2-12s-13
The awnser to this is 2 and also 3
