QUESTION NUMBER ONE IS A AND FOR QUESTION NUMBER TWO IT IS B
Answer: C. M. rupestris, M. eastwoodiae, and M. nelsonii; they put more energy into making rooted branches than they put into making nectar and seeds.
Explanation:
In asexual mode of reproduction the plant does not produce gametes. The plant reproduce through vegetative propagation or spore formation. The plant does not produce nectar as no flowers are produced to attract the pollinators.
In sexual mode of reproduction the plant will develop the gametes and flowers will produce the nectar to attract the pollinators.
Thus on the basis of above explaination, C is the correct option. As the plants will invest more energy in making roots which are the organs for vegetative propagation a process of asexual reproduction.
The correct answer is A.) Sister chromatids pulled to opposite pole, nucleoli form, cytokinesis.
Answer:
The Simplest of Eukaryotic Cells. Microsporidia are intracellular parasites that infect most other eukaryotic cells, although arthropods are the most commonly parasitized. They are the simplest and smallest eukaryotic cells and thus represent a textbook example of reductive evolution [1].
Link: https://designmatrix.wordpress.com/2009/03/10/the-simplest-of-eukaryotic-cells/
