If the maximum length is 0.3 meters from the equillibrium point what is the and the spring oscillates 100 per minute what is it'
1 answer:
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Let the mass of 2500 kg car be and it's velocity be
and the mass of 1500 kg car be
and it's velocity be
.
After the bumping the mass be M and it's velocity be V.
By law of conservation of momentum we have
2500 * 5 + 1500 * 1=4000 * V
V = 14000/4000 = 7/2 = 3.5 m/s
So the velocity of the two-car train = 3.5 m/s
By definition, we have that the mechanical advantage is given by the following equation:
Where,
W: is the load
T: is the tension
Substituting the values in the given equation we have:
Therefore, the mechanical advantage is equal to 5.
Answer:
The mechanical advantage of this machine is:
MA = 5
Where,
W: is the load
T: is the tension
Substituting the values in the given equation we have:
Therefore, the mechanical advantage is equal to 5.
Answer:
The mechanical advantage of this machine is:
MA = 5