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MissTica
3 years ago
7

Give. 1325419200 seconds , convert to years.

Physics
1 answer:
GaryK [48]3 years ago
8 0

Answer:

42 years

Explanation:

1325419200/3.154e+7

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On a certain planet, which is perfectly spherically symmetric, the free-fall acceleration has magnitude g = go at the north pole
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The reason why there is a difference between free-fall acceleration is a centrifugal force.
I attached a diagram that shows how this force aligns with the force of gravity.
From the diagram we can see that:
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Where g' is the free-fall acceleration when there is no centrifugal force, r is the radius of the planet, and w is angular frequency of planet's rotation. \alpha is the latitude.
We can calculate g' and wr^2 from the given conditions in the problem.
g(90)=g_0;\ g_0= g'-w^2rcos^2(90)\\
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Our final equation is:
g=g_0-g_0(a-1)cos^2(\alpha)
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\alpha_c=90^\circ-\alpha
The answer is:
g=g_0-g_0(a-1)cos^2(90-9)=g_0-g_0(a-1)sin^2(9)

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