Answer:
The value is 
Explanation:
From the question we are told that
The weight of the horizontal solid disk is 
The radius of the horizontal solid disk is 
The force applied by the child is 
The time considered is 
Generally the mass of the horizontal solid disk is mathematically represented as
=> 
=> 
Generally the moment of inertia of the horizontal solid disk is mathematically represented as
=> 
=> 
Generally the net torque experienced by the horizontal solid disk is mathematically represented as
=> 
=> 
=> 
Gnerally from kinematic equation we have that
Here 
is the initial angular velocity velocity of the horizontal solid disk which is 
So
=> 
Generally the kinetic energy is mathematically represented as
=> 
=>
Answer:
volume about 1.3 million Earths could fit inside the Sun the mass of the Sun is 1.989 X 10 to the 30 kg about 333000 times the mass of the Earth
Explanation:
step-by-step explanation hope this answer your question
Answer:
The distance from the North Pole to the equator is 
m.
Explanation:
Circumference of Earth = 40,000 km ......................(1)
Distance from the North Pole to the Equator is = 1/4th of the Circumference of Earth ...................... (2)
Let Distance from the North Pole to the Equator be d ,
the equation formed will be ,
d = 1/4 * Circumference of Earth ........(3)......... ( from equation 1 )
put the value of Circumference of Earth in equation (3),
d = 1/4 * 40,000 km
d = 10,000 km
converting km to m ,
d = 10,000 * 
m
d = 1 * 
m
The distance from the North Pole to the equator is m.
ITS C
This element tends to lose 2 electrons to become a 2+ ion, is the correct statement regarding the element calcium. Calcium has 2 electrons in its outer shell and it is easier to lose them than it is to gain enough to become stable. When stable it has 2 more protons than electrons forming a 2+ ion.
Answer:
(a) The total energy of the object at any point in its motion is 0.0416 J
(b) The amplitude of the motion is 0.0167 m
(c) The maximum speed attained by the object during its motion is 0.577 m/s
Explanation:
Given;
mass of the toy, m = 0.25 kg
force constant of the spring, k = 300 N/m
displacement of the toy, x = 0.012 m
speed of the toy, v = 0.4 m/s
(a) The total energy of the object at any point in its motion
E = ¹/₂mv² + ¹/₂kx²
E = ¹/₂ (0.25)(0.4)² + ¹/₂ (300)(0.012)²
E = 0.0416 J
(b) the amplitude of the motion
E = ¹/₂KA²
(c) the maximum speed attained by the object during its motion
