Ask question

Ask question

All categories

3 years ago

10

Two identical projectiles, A and B, are launched with the same initial velocity, but the angle of launch is 75.0° and 15.0° resp

ectively. Which statement is true for the two projectiles?

2 answers:

nekit [7.7K]3 years ago

8 0

Answer:

The answer is A

Explanation:

stepladder [879]3 years ago

7 0

The answer is the range of A and B is equal

You might be interested in

The electric potential, when measured at a point equidistant from two particles that have charges equal in magnitude but of oppo

Reika [66]

Answer:

C) equal to zero

Explanation:

Electric potential is calculated by multiplying constant and charge, then dividing it by distance. The location that we want to measure is equidistant from two particles, mean that the distance from both particles is the same(r2=r1). The charges of the particle have equal strength of magnitude but the opposite sign(q2=-q1). The resultant will be:V = kq/r

ΔV= V1 + V2= kq1/r1 + kq2/r2

ΔV= V1 + V2= kq1/r1 + k(-q1)/(r)1

ΔV= kq1/r1 - kq1/r1

ΔV=0

The electric potential equal to zero

4 0

4 years ago

A self-driving car traveling along a straight section of road starts from rest, accelerating at 2.00 m/s2 until it reaches a spe

Rasek [7]

Answer:

$56.5\ \text{s}$

$21.13\ \text{m/s}$

Explanation:

v = Final velocity

u = Initial velocity

a = Acceleration

t = Time

s = Displacement

Here the kinematic equations of motion are used

$v=u+at\\\Rightarrow t=\dfrac{v-u}{a}\\\Rightarrow t=\dfrac{25-0}{2}\\\Rightarrow t=12.5\ \text{s}$

Time the car is at constant velocity is 39 s

Time the car is decelerating is 5 s

Total time the car is in motion is $12.5+39+5=56.5\ \text{s}$

Distance traveled

$v^2-u^2=2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{25^2-0}{2\times 2}\\\Rightarrow s=156.25\ \text{m}$

$s=vt\\\Rightarrow s=25\times 39\\\Rightarrow s=975\ \text{m}$

$v=u+at\\\Rightarrow a=\dfrac{v-u}{t}\\\Rightarrow a=\dfrac{0-25}{5}\\\Rightarrow a=-5\ \text{m/s}^2$

$s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{0-25^2}{2\times -5}\\\Rightarrow s=62.5\ \text{m}$

The total displacement of the car is $156.25+975+62.5=1193.75\ \text{m}$

Average velocity is given by

$\dfrac{\text{Total displacement}}{\text{Total time}}=\dfrac{1193.75}{56.5}=21.13\ \text{m/s}$

The average velocity of the car is $21.13\ \text{m/s}$ .

6 0

3 years ago

Have I answered this question correctly?

REY [17]

I believe so sorry if you didn’t lakalalallalalalalallalala

5 0

3 years ago

A ship going from sea water to river water has to displace more water to (a) change the buoyant force (b) decrease the buoyant f

grin007 [14]

Answer:

Change, or increase, the buoyant force.

Explanation:

As the salt water of the sea is denser than the river's fresh water, the boat will rise when entering the sea from the river and sink (to increase the buoyant force) when entering the river from the sea.

4 0

3 years ago

In a longitudinal wave, the particles of matter in the medium vibrate by pushing together and moving apart. In a transverse wave

Lilit [14]

Answer:

C. The particles in longitudinal waves travel parallel to the direction of the wave, whereas the particles in transverse waves travel perpendicular to the direction of the wave.

Explanation:

Longitudinal waves are waves that propagates energy from their source by movement of particles in a direction parallel to the wave motion.

Transverse waves produce oscillations that are perpendicular to the direction of propagation.

Examples of longitudinal waves are sound waves, seismic p-waves
Examples of transverse waves are electromagnetic waves

A wave is a disturbance that transmits energy from one point to another.

8 0

3 years ago