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3 years ago

6

4x + 2 = 10 to determine which value of x from the following solution set makes this equation true. {1, 2, 3, or 4}. (Solve the

equation for x=1, x=2, x=3 and x=4, then see which number(s) make the equation TRUE.

1 answer:

zavuch27 [327]3 years ago

6 0

Answer:

Step-by-step explanation:

N

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Help Please I'm Out Of Time ;(

Dafna11 [192]

Answer:

Not true.

Step-by-step explanation:

Whole numbers are integers that are 0 or greater than 0. Since 0 is a whole number and x > 0 does not include 0, the statement is not true. Only the sign ≥ includes 0.

6 0

4 years ago

Jennifer has $3955 in her retirement account, and Reggie has $3935 in his. Jennifer is adding

olga nikolaevna [1]

Answer:

3955, 3963, 3971,

that's jennifer's

3935, 3953, 3971,

that's Reggie's

so Jennifer would have 3971 on the third day, and so would reggie. the amount would be 3971

4 0

3 years ago

Translate this sentence into an equation.

gregori [183]

63 = 10 + m
hope this helps :)

4 0

3 years ago

I need you guy’s help answer thanks so much

e-lub [12.9K]

I believe it’s C, hopefully this helps !!

6 0

3 years ago

Use the power reduction formulas to rewrite the expression. (Hint: Your answer should not contain any exponents greater than 1.)

Lapatulllka [165]

Some useful relations and identities:

$\tan x=\dfrac{\sin x}{\cos x}$

$\sin^2x=\dfrac{1-\cos2x}2$

$\cos^2x=\dfrac{1+\cos2x}2$

By the first relation, we have

$\tan^2x\sin^3x=\dfrac{\sin^5x}{\cos^2x}=\dfrac{(\sin^2x)^2\sin x}{\cos^2x}$

Applying the two latter identities, we get

$\dfrac{\left(\frac{1-\cos2x}2\right)^2\sin x}{\frac{1+\cos2x}2}=\dfrac{\frac{1-2\cos2x+\cos^22x}4\sin x}{\frac{1+\cos2x}2}=\dfrac{(1-2\cos2x+\cos^22x)\sin x}{2(1+\cos2x)}$

We can apply the third identity again:

$\dfrac{(1-2\cos2x+\cos^22x)\sin x}{2(1+\cos2x)}=\dfrac{\left(1-2\cos2x+\frac{1+\cos4x}2\right)\sin x}{2(1+\cos2x)}=\dfrac{(3-4\cos2x+\cos4x)\sin x}{4(1+\cos2x)}$

and this is probably as far as you have to go, but by no means is it the only possible solution.

8 0

3 years ago