4x + 2 = 10 to determine which value of x from the following solution set makes this equation true. {1, 2, 3, or 4}. (Solve the
1 answer:
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Answer:
21 pieces of chickens.
Step-by-step explanation:
Given:
The farmer has a total of 40 animals. ( cows and chicken )
He counts the legs of all his animals and realizes he has a total of 118 legs.
Question asked:
How many chickens does the farmer have ?
Solution:
Let number of chickens =
Then number of cows =
Now, as here given that total number of legs are 118 of all the animals, and as we know that a chicken has two legs and cow has four legs, hence the equation will be :
<u>Total number of legs = Number of legs having chickens + Number of legs having cows</u>
Subtracting both sides by 160
By adding both sides by minus
By dividing both sides by 2
Hence, farmer have 21 pieces of chickens.
Answer:
The "probability that a given score is less than negative 0.84" is .
Step-by-step explanation:
From the question, we have:
- The random variable is <em>normally distributed</em> according to a <em>standard normal distribution</em>, that is, a normal distribution with
and
.
- We are provided with a <em>z-score</em> of -0.84 or
.
Preliminaries
A z-score is a standardized value, i.e., one that we can obtain using the next formula:
[1]
Where
- <em>x</em> is the <em>raw value</em> coming from a normal distribution that we want to standardize.
- And we already know that
and
are the mean and the standard deviation, respectively, of the <em>normal distribution</em>.
A <em>z-score</em> represents the <em>distance</em> from in <em>standard deviations</em> units. When the value for z is <em>negative</em>, it "tells us" that the raw score is <em>below</em>
. Conversely, when the z-score is <em>positive</em>, the standardized raw score, <em>x</em>, is <em>above</em> the mean,
.
Solving the question
We already know that or that the standardized value for a raw score, <em>x</em>, is <em>below</em>
in <em>0.84 standard deviations</em>.
The values for probabilities of the <em>standard normal distribution</em> are tabulated in the <em>standard normal table, </em>which is available in Statistics books or on the Internet and is generally in <em>cumulative probabilities</em> from <em>negative infinity</em>, - , to the z-score of interest.
Well, to solve the question, we need to consult the <em>standard normal table </em>for . For this:
- Find the <em>cumulative standard normal table.</em>
- In the first column of the table, use -0.8 as an entry.
- Then, using the first row of the table, find -0.04 (which determines the second decimal place for the z-score.)
- The intersection of these two numbers "gives us" the cumulative probability for z or
.
Therefore, we obtain for this z-score, or a slightly more than 20% (20.045%) for the "probability that a given score is less than negative 0.84".
This represent the area under the <em>standard normal distribution</em>, , at the <em>left</em> of <em>z = -0.84</em>.
To "draw a sketch of the region", we need to draw a normal distribution <em>(symmetrical bell-shaped distribution)</em>, with mean that equals 0 at the middle of the distribution, , and a standard deviation that equals 1,
.
Then, divide the abscissas axis (horizontal axis) into <em>equal parts</em> of <em>one standard deviation</em> from the mean to the left (negative z-scores), and from the mean to the right (positive z-scores).
Find the place where z = -0.84 (i.e, below the mean and near to negative one standard deviation, , from it). All the area to the left of this value must be shaded because it represents
and that is it.
The below graph shows the shaded area (in blue) for for
.
