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lawyer [7]
4 years ago
11

A 0.060 kg ball hits the ground with a speed of -32m/s. The ball is in contact with the ground for 45 milliseconds and the groun

d exerts a +55 N force on the ball. What is the magnitude of the velocity after it hits the ground?
a. 9.3m/sB.12m/sC.41m/sD.73m/s
Physics
1 answer:
quester [9]4 years ago
8 0

A:

Impulse is given by:

FΔt = Δp

We know the mass and velocity and we need the final velocity so lets break this down and isolate

FΔt = mv(final) - mv(initial)

Factor out m

FΔt = m(v(final) - v(initial))

FΔt / m = v(final) - v(initial)

Add v initial

(FΔt / m) + v(initial) = v(final)

(55x45ms / 0.060) - 32 = v(final)

v(final) = +9.25 m/s or 9.3

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a water wave has a speed of 23.0 meters/second. if the waves frequency is 0.0680 hertz, what is the wavelength
USPshnik [31]

Answer:

 Using the Fundamental Equation of Wave, we have:

Explanation:

7 0
3 years ago
In which reaction are the atoms of elements rearranged?
NNADVOKAT [17]

Answer:

D. Hydrogen combines with oxygen to form water.

Explanation:

Hydrogen combining with oxygen to form water is a typical example of chemical reaction.

During a chemical reaction, atoms of elements are rearranged. Most chemical reactions obey the law of conservation of mass which states that "matter is neither created nor destroyed in a chemical reaction but atoms are simply rearranged".

The other choices given are nuclear reactions. In such reactions, atoms are not rearranged but are simply destroyed and made in the process.

4 0
3 years ago
Suppose that 2 J of work is needed to stretch a spring from its natural length of 34 cm to a length of 46 cm. (a) How much work
dlinn [17]

Answer:

0.83 J of work

Explanation:

2 J of work is required to stretch a spring from 34cm to 46cm

So that is 12cm stretched with 2 J of work

We can make that 6cm for 1 J of work

So, we need the find the work for stretching 36cm to 41cm

Which is 5cm

So, What is the work required to stretch 5cm?

1 J of work for 6cm

x work for 5cm

So, by proportion method

1 : 6 :: x : 5

6 * x = 1 * 5

6x = 5

x = 5/6

= 0.83

So to stretch 36cm to 41cm we need 0.83 J of work

4 0
3 years ago
a driver travels 135 km, east in 1.5 h, stops for 45 minutes for lunch, and then resumes driving for the next 2.0 h through a di
daser333 [38]

Answer:

v = 98.75 km/h

Explanation:

Given,

The distance driver travels towards the east, d₁ = 135 km

The time period of the travel, t₁ = 1.5 h

The halting time, tₓ = 46 minutes

The distance driver travels towards the east, d₂ = 215 km

The time period of the travel, t₁ = 2 h

The average speed of the vehicle before stopping

                                    v₁ = d₁/t₁

                                        = 135/1.5

                                       = 90 km/h

The average speed of vehicle after stopping

                                    v₂ = d₂/t₂

                                         = 215/2

                                        = 107.5 km/h

The total average velocity of the driver

                                      v = (v₁ +v₂) /2

                                         = (90 + 107.5)/2

                                         = 98.75 km/h

Hence, the average velocity of the driver, v = 98.75 km/h

7 0
4 years ago
When solid surfaces slide over each other, the kind of friction that occurs is called sliding friction.
LekaFEV [45]

Answer:

True

Explanation:

A sled sliding across snow or ice. Skis sliding against snow. A person sliding down a slide is an example of sliding friction. A coaster sliding against a table. Two cards in a deck sliding against each other. All of these are examples of sliding friction.

Hope this helps! :)

6 0
4 years ago
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