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aniked [119]
3 years ago
8

What does 125 have in common with a^3 when 125 is written as a power?

Mathematics
2 answers:
Blababa [14]3 years ago
6 0
5*5*5=125
a^3=125


a=5

The one before me answered correctly.
mestny [16]3 years ago
5 0

125

2

3

Rewrite  

2

3

as a product.

Tap for more steps...

(

125

1

3

)

2

Simplify.

Tap for more steps...

5

2

Raise  

5

to the power of  

2

.

25

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How much is 5a(6b+12)
andreev551 [17]
When writing an expression in expanded form, we just need to multiply what's outside the parentheses by everything that is inside the parentheses.

5a (6b + 12)

(5a * 6b) + (5a * 12)

30ab + 60a

And that is our answer.
5a (6b + 12) in expanded form is 30ab + 60a.
Hope that helped =)
6 0
3 years ago
Read 2 more answers
Type the ordered pair that is the solution to these questions. <br> 3x-y=13
Dvinal [7]

Answer:

Here's 3 ordered pairs:

(0,-13)(1,-10)(2,-7)

Step-by-step explanation:

They should all be correct. It doesn't matter which one you choose.

3 0
3 years ago
a certain pharmaceutical company know that, on average 4% of a certain type of pill has an ingredient that is below the minimum
FinnZ [79.3K]

Using the binomial distribution, it is found that there is a 0% probability that fewer that 5 in a sample of 20 pills will be acceptable.

For each pill, there are only two possible outcomes, either it is acceptable, or it is not. The probability of a pill being acceptable is independent of any other pill, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • The sample has 20 pills, hence n = 20.
  • 100 - 4 = 96% are acceptable, hence p = 0.96

The probability that <u>fewer that 5 in a sample of 20 pills</u> will be acceptable is:

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{20,0}.(0.96)^{0}.(0.04)^{20} = 0

P(X = 1) = C_{20,1}.(0.96)^{1}.(0.04)^{19} = 0

P(X = 2) = C_{20,2}.(0.96)^{2}.(0.04)^{18} = 0

P(X = 3) = C_{20,3}.(0.96)^{3}.(0.04)^{17} = 0

P(X = 4) = C_{20,4}.(0.96)^{4}.(0.04)^{16} = 0

0% probability that fewer that 5 in a sample of 20 pills will be acceptable.

A similar problem is given at brainly.com/question/24863377

8 0
2 years ago
500+100 = ?? A700 B800 C600
nekit [7.7K]

Answer:

C

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The females prefer drama movies is the correct one. The third one

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