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Alex17521 [72]
3 years ago
10

Chapter 2.4.1. The ______ energy lost by the inward movement of nickel-iron within a differentiating molten planetary body would

be converted first into _______ energy and then into ______ energy. a. momentum, thermal, gravitational b. gravitational, kinetic, thermal c. thermal, momentum, kinetic d. kinetic, thermal, gravitational
Chemistry
1 answer:
Gwar [14]3 years ago
8 0

Answer:b. gravitational, kinetic, thermal

Explanation:

The above explains the mechanism of the core forming process on earth/planet.

It is believed that this process might has contributed significantly to a planet's early stages heating. The time when these core-forming event happened is thought to have been mainly completed very early when Earth was young . The type of this event rather than it being seen as a single catastrophic event, it is likely to have been as a result of contractions on the earth severally.

The addition of partially differentiated material from another giant impact the rate of this spasm , and it increases each time the planet's mass is to increased.

This is a little on the history of planetary evolution.

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Answer:

5.702 mol K₂SO₄

General Formulas and Concepts:

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Compounds
  • Moles

<u>Stoichiometry</u>

  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

[Given] 993.6 g K₂SO₄

[Solve] moles K₂SO₄

<u>Step 2: Identify Conversions</u>

[PT] Molar Mass of K: 39.10 g/mol

[PT] Molar Mass of S: 32.07 g/mol

[PT] Molar mass of O: 16.00 g/mol

Molar Mass of K₂SO₄: 2(39.10) + 32.07 + 4(16.00) = 174.27 g/mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                       \displaystyle 993.6 \ g \ K_2SO_4(\frac{1 \ mol \ K_2SO_4}{174.27 \ g \ K_2SO_4})
  2. [DA] Divide [Cancel out units]:                                                                         \displaystyle 5.7015 \ mol \ K_2SO_4

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 4 sig figs.</em>

5.7015 mol K₂SO₄ ≈ 5.702 mol K₂SO₄

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