Answer:
hey you wanna get it right try this one: 48.0 kcal
was released... at constant pressure.
Explanation:
Empirical formula mass
Molecular fornula mass:-180g/mol
- n=Molecular formula mass/Empirical formula mass
- m=180/30
- n=6
Molecular formula:-
- n×Empirical formula
- 6(CH_2O
- C_6H_12 O_6
Percent strength (% w/w) of a solution is defined as the amount of solute present in 100 g of the solution.
Given data:
Mass of the solute, potassium chloride = 62.5 g
Volume of water (solution) = 187.5 ml
We know that the density of water = 1 g/ml
Therefore, the mass corresponding to the given volume of water
= 187.5 ml * 1 g/1 ml = 187.5 g
We have a solution of 62.5 g of potassium chloride in 187.5 g water
Therefore, amount of solute in 100 g of water= 62.5 * 100/187.5 = 33.33
The percentage strength = 33.33 %