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3 years ago

Consider this row in the periodic table of elements. As we move from left to right, across the row, the elements

Chemistry

1 answer:

djverab [1.8K]3 years ago

6 0

Answer:

uhhh i do not know this but we are learning at my school i could give you the answer soon i you want

Explanation:

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For the chemical reaction:

Kamila [148]

Answer:

Volume of ammonia produced = 398.7 dm³

Explanation:

Given data:

Volume of N₂ = 200 dm³

Pressure and temperature = standard

Volume of ammonia produced = ?

Solution:

Chemical equation:

N₂ + 3H₂ → 2NH₃

Number of moles of N₂:

PV = nRT

1 atm× 200 L = n× 0.0821 atm.L/mol.K × 273 K

n = 200 atm.L /22.41 atm.L/mol

n = 8.9 mol

Now we will compare the moles of ammonia and nitrogen.

N₂ : NH₃

1 : 2

8.9 : 2/1×8.9 = 17.8 mol

Volume of ammonia:

1 mole of any gas occupy 22.4 dm³ volume

17.8 mol ×22.4 dm³/1 mol = 398.7 dm³

7 0

3 years ago

A chemical reaction takes place inside a flask submerged in a water bath. The water bath contains 8.10kg of water at 33.9 degree

lions [1.4K]

Answer:

The new temperature of the water bath 32.0°C.

Explanation:

Mass of water in water bath ,m= 8.10 kg = 8100 g ( 1kg = 1000g)

Initial temperature of the water = $T_1=33.9^oC=33.9+273K=306.9 K$

Final temperature of the water = $T_2$

Specific heat capacity of water under these conditions = c = 4.18 J/gK

Amount of energy lost by water = -Q = -69.0 kJ = -69.0 × 1000 J

( 1kJ=1000 J)

$Q=m\times c\times \Delta T=m\times c\times (T_2-T_1)$

$-69.0\times 1000 J=8100 g\times 4.18 J/g K\times (T_2-306.9 K)$

$-69,000.0 J=8100 g\times 4.18 J/g K\times (T_2-306.9 K)$

$T_2=304.86 K=304.86 -273^oC=31.86^oC\approx 32.0^oC$

The new temperature of the water bath 32.0°C.

5 0

4 years ago

Which of the following is a half-reaction? A. Zn+CuSO4−> B. 2Cl−−>Cl2+2e− C. H2+1/2O2−>H2O D. −>Cu+ZnSO4

malfutka [58]

Answer:

2Cl——>Cl2+2e-

Explanation:

It shows an electron loss or gain

8 0

3 years ago

A student made this model of a carbon dioxide molecule. its has one carbon atom and two oxygen atoms what is the correct way to

ExtremeBDS [4]

The proper way to chemically write carbon dioxide is CO2

4 0

4 years ago

Read 2 more answers

How many grams of iron(III) oxide (Fe(OH)3) may theoretically be produced from 85.0 g FeCl3?

Crank

Answer:

56.0 g

Explanation:

Calculation of the moles of $FeCl_3$ as:-

Mass = 85.0 g

Molar mass of $FeCl_3$ = 162.2 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{85.0\ g}{162.2\ g/mol}$

$Moles= 0.52404\ mol$

According to the reaction:-

$FeCl_3+3 NaOH\rightarrow Fe(OH)_3+3 NaCl$

1 mole of $FeCl_3$ on reaction forms 1 mole of $Fe(OH)_3$

Also,

0.52404 mole of $FeCl_3$ on reaction forms 0.52404 mole of $Fe(OH)_3$

Moles of $Fe(OH)_3$ = 0.52404 moles

Molar mass of $Fe(OH)_3$ = 106.867 g/mol

Mass = Moles*Molar mass = $0.52404\times 106.867\ g$ = 56.0 g

8 0

3 years ago