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notka56 [123]
2 years ago
13

In a particular redox reaction, no−2no2− is oxidized to no−3no3− and fe3 fe3 is reduced to fe2 fe2. complete and balance the equ

ation for this reaction in acidic solution. phases are optional
Chemistry
1 answer:
anyanavicka [17]2 years ago
3 0

Balanced chemical equation is  -  3Fe2+ + NO3- + 4H+ → 3Fe3+ + NO + 2H2O

Fe2+ + NO3- + H+ → Fe3+ + NO3- + NO + H2O

Fe+22+ + N+5O-23- + H+1+ → Fe+33+ + N+5O-23- + N+2O-2 + H+12O

3Fe2+ + NO3- + 4H+ → 3Fe3+ + NO + 2H2O

A balanced chemical equation specifies the quantities of reactants and products required to meet the Law of Conservation of Mass. This signifies that there is the same number of each sort of atom on the left side of the equation as there are on the right side. The rule of a balanced chemical equation is used to determine if two weights put on opposing sides of the fulcrum will balance each other.

To learn more Balanced chemical equations about please visit -
brainly.com/question/15052184
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A dilute solution is prepared by transferring 40.00 ml of a 0.3433 m stock solution to a 750.0 ml volumetric flask and diluting
alina1380 [7]
We are given with the initial volume of the substance and the molarity. The first thing that needs to be done is to multiply the equation in order to obtain the number of moles such as shown below.
  
    number of moles = (40 mL) x (1 L / 1000 mL) x (0.3433 moles / L)
           number of moles = 0.013732 moles

To get the value of the molarity of the diluted solution, we divide the number of moles by the total volume.
          molarity = (0.013732 moles) / (750 mL / 1000 mL/L) = 0.0183 M

Similarly, we can solve for the molarity by using the equation,
           M₁V₁ = M₂V₂
Substituting the known values in the equation,
     (0.3433 M)(40 mL) = M₂(750 mL)
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5 0
3 years ago
Ethylenediamine (en) forms an octahedral complex with Ni2+(aq) with the formula [Ni(en)3]2+. Ni2+(aq) + 3 en ⇌ [Ni(en)3]2+(aq) K
yawa3891 [41]

Answer:

3.125\times 10^{-19} mol/L is the concentration of Ni^{2+}(aq) in the solution.

Explanation:

Ni^{2+}(aq) + 3 en\rightleftharpoons [Ni(en)_3]^{2+}(aq)

Concentration of nickel ion = [Ni^{2+}]=x

Concentration of nickel complex= [[Ni(en)_3]^{2+}]=\frac{0.16 mol}{2 L}=0.08 mol/L

Concentration of ethylenediamine = [en]=\frac{0.80 mol}{2 L}=0.40 mol/L

The formation constant of the complex = K_f=4.0\times 10^{18}

The expression of formation constant is given as:

K_f=\frac{[[Ni(en)_3]^{2+}]}{[Ni^{2+}][en]^3}

4.0\times 10^{18}=\frac{0.08 mol/L}{x\times (0.40 mol/L)^3}

x=\frac{0.08 mol/L}{4.0\times 10^{18}\times (0.40 mol/L)^3}

x=3.125\times 10^{-19} mol/L

3.125\times 10^{-19} mol/L is the concentration of Ni^{2+}(aq) in the solution.

6 0
3 years ago
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