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notka56 [123]
2 years ago
13

In a particular redox reaction, no−2no2− is oxidized to no−3no3− and fe3 fe3 is reduced to fe2 fe2. complete and balance the equ

ation for this reaction in acidic solution. phases are optional
Chemistry
1 answer:
anyanavicka [17]2 years ago
3 0

Balanced chemical equation is  -  3Fe2+ + NO3- + 4H+ → 3Fe3+ + NO + 2H2O

Fe2+ + NO3- + H+ → Fe3+ + NO3- + NO + H2O

Fe+22+ + N+5O-23- + H+1+ → Fe+33+ + N+5O-23- + N+2O-2 + H+12O

3Fe2+ + NO3- + 4H+ → 3Fe3+ + NO + 2H2O

A balanced chemical equation specifies the quantities of reactants and products required to meet the Law of Conservation of Mass. This signifies that there is the same number of each sort of atom on the left side of the equation as there are on the right side. The rule of a balanced chemical equation is used to determine if two weights put on opposing sides of the fulcrum will balance each other.

To learn more Balanced chemical equations about please visit -
brainly.com/question/15052184
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<u>Answer:</u> The concentration of original sulfuric acid solution is 1.62 M

<u>Explanation:</u>

Let the original concentration of sulfuric acid be 'x' M

To calculate the molarity of the diluted solution, we use the equation:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the concentrated sulfuric acid solution

M_2\text{ and }V_2 are the molarity and volume of diluted sulfuric acid solution

We are given:

M_1=xM\\V_1=25.00mL\\M_2=?M\\V_2=250.0mL

Putting values in above equation, we get:

x\times 25.00=M_2\times 250.0\\\\M_2=\frac{x\times 25.0}{250}=\frac{x}{10}

Now, to calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=2\\M_1=\frac{x}{10}M\\V_1=10.00mL\\n_2=1\\M_2=0.1790M\\V_2=18.07mL

Putting values in above equation, we get:

2\times \frac{x}{10}\times 10.00=1\times 0.1790\times 18.07\\\\x=\frac{1\times 0.1790\times 18.07\times 10}{2\times 10.00}=1.62M

Hence, the concentration of original sulfuric acid solution is 1.62 M

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