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Luda [366]
2 years ago
6

There are 9.88x1023 molecules of O2 available.

Chemistry
1 answer:
blondinia [14]2 years ago
7 0

Answer:

1.64 moles O₂

Explanation:

Part A:

Remember 1 mole of particles = 6.02 x 10²³ particles

So, the question becomes, how many  '6.02 x 10²³'s are there in 9.88 x 10²³ molecules of O₂?

This implies a division of given number of particles by 6.02 x 10²³ particles/mole.

∴moles O₂ = 9.88 x 10²³ molecules O₂ / 6.02 x 10²³ molecules O₂ · mole⁻¹ = 1.64 mole O₂

_______________

Part B needs an equation (usually a combustion of a hydrocarbon).

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.950 L of .420 M H2SO4 is mixed with .900 L of .260 M KOH. What concentration of sulfuric acid remains after neutralization?
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H₂SO₄:

V=0,95L
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n = CmV = 0,42mol/L * 0,95L = 0,399mol

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H₂SO₄            +           2KOH ⇒ K₂SO₄ + 2H₂O
1mol                :           2mol
0,399mol         :           0,234mol
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reamins: 0,399mol - 0,117mol = 0,282mol

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3 years ago
What is the representative particle for barium chloride?
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